请帮忙看一下，这个程序问题在哪里，调试时的错误显示已经给出
#include <stdio.h>#include <math.h>
int main()
{
double price, area, percent,rate, Total, Fisrt_Payment, Total_Loan, Total_Repayment, Interest_for_payment, Payment_per_month, pricial, rate_per_month;
int year;
printf("请输入单价(元/平方):");
scanf("%f",&price);
printf("请输入面积:");
scanf("%f",&area);
printf("请输入按揭成数:");
scanf("%f",&percent);
printf("请输入按揭年数:");
scanf("%d",&year);
printf("请输入当前基准年利率:");
scanf("%f",&rate);
rate_per_month = rate / 12 / 100;//月利率
Total = price * area; // 房屋总价
pricial= Total * (percent/10); //还款本金
Payment_per_month = pricial * (rate_per_month*pow((1+rate_per_month), year*12)) / ((pow(1+ rate_per_month), year*12) -1.0); // 月还款额
Total_Repayment = (year * 12) * Payment_per_month; // 还款总额
Fisrt_Payment = Total - Total_Loan; //首付
Total_Repayment = Payment_per_month* year *12;//
Total_Loan = pricial; //贷款总额
Interest_for_payment = Total_Repayment - Total_Loan; //支付利息
printf("========报告结果========\n");
printf("房款总额：%.2f\n",Total);
printf("首期付款: %.2f\n",Fisrt_Payment);
printf("贷款总额: %.2f\n",Total_Loan);
printf("还款总额: %.2f\n",Total_Repayment);
printf("支付利息：%.2f\n",Interest_for_payment);
printf("月均还款: %.2f\n",Payment_per_month);
return 0;
}
调试的时候，说Payment_per_month = pricial * (rate_per_month*pow((1+rate_per_month), year*12)) / ((pow(1+ rate_per_month), year*12) -1); 语句错误，错误内容如下：
too few arguments to function 'pow'
pow函数的调用是需要两个参数的，注意一下 “月还款额” 那一行后面的pow括号的位置 Payment_per_month = pricial * (rate_per_month*pow((1+rate_per_month), year*12)) / ((pow((1+ rate_per_month), year*12)) -1.0); // 月还款额
Payment_per_month = pricial * (rate_per_month*pow((1+rate_per_month), year*12)) / ((pow((1+ rate_per_month), year*12)) -1.0); // 月还款额
少了一对括号 检查出来了，POW前的括号打错了，哈哈！
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