Server-bao 发表于 2019-7-3 16:48:01

新人求助

编写一个程序,生成以下输出:
For he's a jolly good fellow!
For he's a jolly good fellow!
For he's a jolly good fellow!
Which nobody can deny!
除了 main()函数以外,该程序还要调用两个自定义函数:一个名为jolly(),用于打印前 3 条消息,调用一次打印一条;另一个函数名为deny(),打印最后一条消息。

newu 发表于 2019-7-3 16:57:04

python吗?

newu 发表于 2019-7-3 16:59:27

如果是Python的话
def main():
    jolly()
    deny()

def jolly():
    for i in range(3):
      print("For he's a jolly good fellow!")

def deny():
    print("Which nobody can deny!")

main() # 调用

结果:
For he's a jolly good fellow!
For he's a jolly good fellow!
For he's a jolly good fellow!
Which nobody can deny!
>>>

Server-bao 发表于 2019-7-3 17:04:58

newu 发表于 2019-7-3 16:59
如果是Python的话




是C语言

newu 发表于 2019-7-3 17:12:13

Server-bao 发表于 2019-7-3 17:04
是C语言

#include<stdio.h>

void jolly() {
        printf("For he's a jolly good fellow!\n");
}

void deny() {
        printf("Which nobody can deny!\n");
}

int main()
{
        int i;
        for (i=0; i<3; i++) {
                jolly();
        }
        deny();
        return 0;
}
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