Seawolf 发表于 2019-9-1 08:24:12

leetcode 771. Jewels and Stones

You're given strings J representing the types of stones that are jewels, and S representing the stones you have.Each character in S is a type of stone you have.You want to know how many of the stones you have are also jewels.

The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".

Example 1:

Input: J = "aA", S = "aAAbbbb"
Output: 3
Example 2:

Input: J = "z", S = "ZZ"
Output: 0
Note:

S and J will consist of letters and have length at most 50.
The characters in J are distinct.

class Solution {
    public int numJewelsInStones(String J, String S) {
      
      if(S.length() == 0) return 0;
      
      char[] charArray = S.toCharArray();
      int count = 0;
      
      for(char i : charArray){
            
            if(J.indexOf(i) != -1){
               
                count++;
            }
      }
      
      return count;
    }
}
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