Type error 的问题
def question(heads, legs):rabbit_number_max = legs // 4
rabbit_number = 0
while True:
chicken_number = (legs - rabbit_number * 4) / 2
if chicken_number == int(chicken_number) and rabbit_number + chicken_number == heads:
return (chicken_number, rabbit_number)
elif rabbit_number <= rabbit_number_max:
rabbit_number += 1
else:
print('题目错误啦*_*!此题无解!')
def number(heads, legs):
if heads <= 0 or heads != int(heads):
print('头的参数错误T_T!请输入一个正整数!')
heads = float(input('请重新输入头的个数:'))
elif legs <= 0 or legs != int(legs):
print('脚的参数错误T_T!请输入一个正整数!')
legs = float(input('请重新输入:'))
else:
return(heads, legs)
heads = float(input('请输入头的个数:'))
legs = float(input('请输入脚的个数:'))
(true_heads, true_legs) = number(heads, legs)
(chicken_number, rabbit_number) = question(true_heads, true_legs)
print('鸡的个数是%d, 兔的个数是%d' % (int(chicken_number), int(rabbit_number)))
请输入头的个数:34.5
请输入脚的个数:94
头的参数错误T_T!请输入一个正整数!
请重新输入头的个数:35
Traceback (most recent call last):
File "C:/Users/Documents/学习/python/作业簿/鸡兔同笼.py", line 27, in <module>
(true_heads, true_legs) = number(heads, legs)
TypeError: cannot unpack non-iterable NoneType object def question(heads, legs):
rabbit_number_max = legs // 4
rabbit_number = 0
while True:
chicken_number = (legs - rabbit_number * 4) / 2
if chicken_number == int(chicken_number) and rabbit_number + chicken_number == heads:
return (chicken_number, rabbit_number)
elif rabbit_number <= rabbit_number_max:
rabbit_number += 1
else:
print('题目错误啦*_*!此题无解!')
def number(heads, legs):
if heads <= 0 or heads != int(heads):
print('头的参数错误T_T!请输入一个正整数!')
heads = float(input('请重新输入头的个数:'))
elif legs <= 0 or legs != int(legs):
print('脚的参数错误T_T!请输入一个正整数!')
legs = float(input('请重新输入:'))
return(heads, legs)
heads = float(input('请输入头的个数:'))
legs = float(input('请输入脚的个数:'))
(true_heads, true_legs) = number(heads, legs)
(chicken_number, rabbit_number) = question(true_heads, true_legs)
print('鸡的个数是%d, 兔的个数是%d' % (int(chicken_number), int(rabbit_number))) 几个错误,解释看代码里的注释:
def question(heads, legs):
rabbit_number_max = legs // 4
rabbit_number = 0
while True:
chicken_number = (legs - rabbit_number * 4) / 2
if chicken_number == int(chicken_number) and rabbit_number + chicken_number == heads:
return (chicken_number, rabbit_number)
elif rabbit_number <= rabbit_number_max:
rabbit_number += 1
else:
print('题目错误啦*_*!此题无解!')
break #无解就无限循环了,至少加个break吧,然后默认返回None
def number(heads, legs):
if heads <= 0 or heads != int(heads):
print('头的参数错误T_T!请输入一个正整数!')
heads = float(input('请重新输入头的个数:'))
#没有返回呀,默认返回None
elif legs <= 0 or legs != int(legs):
print('脚的参数错误T_T!请输入一个正整数!')
legs = float(input('请重新输入:'))
#同上
# else:这样改就有正常的返回了
return(heads, legs)
heads = float(input('请输入头的个数:'))
legs = float(input('请输入脚的个数:'))
(true_heads, true_legs) = number(heads, legs)
if question(true_heads, true_legs)!=None: #加个判断,不然无解还运行下面语句就报错
(chicken_number, rabbit_number) = question(true_heads, true_legs)
print('鸡的个数是%d, 兔的个数是%d' % (int(chicken_number), int(rabbit_number)))
同意楼上两位的代码。(至少可以顺利执行)
出现错误的原因是当遇到其他情况时number函数并不会返回一个元组,这样就没有办法再把参数传入question函数。
在你的实验中,输出了
头的参数错误T_T!请输入一个正整数!
之后,会直接执行下一行代码
(chicken_number, rabbit_number) = question(true_heads, true_legs)
因此return需要在任何条件都实现才可以继续进行。除了楼上的解决方式,你还可以:
1.在number函数中添加一个while循环以保证输入正确时才会跳出函数
2.在执行代码区使用try except语句避免报错
希望对你有所帮助
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