Python 实现 itertools.count
from numbers import Numberdef count(start, step=1):
if isinstance(start,Number) and isinstance(step,Number):
while True:
yield start
start+=step
else:
raise TypeError("a number is required")如果代码有问题,欢迎在评论区指出{:10_323:} 不应该是一个类吗 zltzlt 发表于 2020-4-2 18:59
不应该是一个类吗
其实差别也不大,全凭心情{:10_262:}from numbers import Number
class count:
def __init__(self,start,step=1):
if isinstance(start,Number) and isinstance(step,Number):
self.__start=start
self.__step=step
else:
raise TypeError("a number is required")
def __iter__(self):
return self
def __next__(self):
temp=self.__start
self.__start+=self.__step
return temp 看不懂,来学习
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