能帮忙看看中间的怎么简化吗?
time = 5while time:
temp = input('请输入一个年份:')
if not temp.isdigit():
temp = input("抱歉,您的输入有误,请输入一个整数:")
year = int(temp)
if year/400 == int(year/400):
print(temp + ' 是闰年!')
else:
if (year/4 == int(year/4)) and (year/100 != int(year/100)):
print(temp + ' 是闰年!')
else:
print(temp + ' 不是闰年!')
else:
year = int(temp)
if year/400 == int(year/400):
print(temp + ' 是闰年!')
else:
if (year/4 == int(year/4)) and (year/100 != int(year/100)):
print(temp + ' 是闰年!')
else:
print(temp + ' 不是闰年!')
time = time - 1
print('结束了~')
整数和非整数判定后感觉还是很繁琐,尝试改了几次都不成功{:9_220:} 去掉判断还能更少:
n = input("请输入一个年份:")
while not n.isdigit():
n = input("输入错误,请重新输入:")
n = int(n)
if not n % 400 or (n % 100 and not n % 4):
print("%d 是闰年!" % n)
else:
print("%d 不是闰年!" % n) 看了看你的代码,为何不用取余呢?
用除法多麻烦,而且就是用除法
你也得用地板除啊 试试用取余运算,逻辑要简单很多的 while True:
temp = input('请输入一个年份:')
while not temp.isdigit():
temp = input("抱歉,您的输入有误,请输入一个整数:")
year = int(temp)
if year/400 == int(year/400):
print(temp + ' 是闰年!')
else:
if (year/4 == int(year/4)) and (year/100 != int(year/100)):
print(temp + ' 是闰年!')
else:
print(temp + ' 不是闰年!')
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