如何给unsigned char *赋值
C语言小白请教,想要给函数中的unsigned char *参数赋值,照着网上的写了怎么都报错,要怎么改main函数里的赋值代码?报错是: invalid conversion from 'unsigned char' to 'unsigned char*' [-fpermissive]
#include <stdio.h>
void seedToKey(unsigned char *seed,int seedlength,unsigned char *key, unsigned int keylength);
main()
{
int seedlength=2;
unsigned char *seed;
unsigned char a;
a = 0;
a=1;
seed=&a;
unsigned char *key;
unsigned char b;
key=&b;
int keylength=0;
seedToKey(*seed,seedlength,*key,keylength);
}
void seedToKey(unsigned char *seed,int seedlength,unsigned char *key, unsigned int keylength)
{
keylength = seedlength*2;
printf("%3.0f",keylength);
int i=0;
for(i=0;i!=seedlength*2;i++)
{
if(i>=seedlength)
key = seed;
else
key = seed;
}
}
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https://www.baidu.com/s?ie=utf-8&f=8&rsv_bp=1&rsv_idx=1&tn=62095104_26_oem_dg&wd=%E5%A6%82%E4%BD%95% ...
跳转到了百度首页,大佬在教育我么{:10_285:} 你这不是给unsigned char*赋值的问题吧
void seedToKey(unsigned char *seed,int seedlength,unsigned char *key, unsigned int keylength)
函数中第一个和第三个参数都是unsigned char* 类型,但是你在调用函数的时候,写的却不是指针,
第18行,seedToKey(*seed,seedlength,*key,keylength); *seed不是指针,而是指针指向的内容,类型其unsigned char,不加* 才是指针。
另外第23行printf和石化符号用错了,keylength是unsigned int 格式化输出应该用%u,而不是%f
#include <stdio.h>
void seedToKey(unsigned char *seed,int seedlength,unsigned char *key, unsigned int keylength);
main()
{
int seedlength=2;
unsigned char *seed;
unsigned char a;
a = 0;
a=1;
seed=&a;
unsigned char *key;
unsigned char b;
key=&b;
int keylength=0;
seedToKey(seed,seedlength,key,keylength);
}
void seedToKey(unsigned char *seed,int seedlength,unsigned char *key, unsigned int keylength)
{
keylength = seedlength*2;
printf("%u",keylength);
int i=0;
for(i=0;i!=seedlength*2;i++)
{
if(i>=seedlength)
key = seed;
else
key = seed;
}
} FC的注册很坑 发表于 2020-4-7 10:55
跳转到了百度首页,大佬在教育我么
不是,不要光点击蓝色的部分
把所有的字符放进地址栏 qiuyouzhi 发表于 2020-4-7 10:56
不是,不要光点击蓝色的部分
把所有的字符放进地址栏
2个都试了,都是跳转到百度首页 FC的注册很坑 发表于 2020-4-7 10:58
2个都试了,都是跳转到百度首页
额,好吧
那你看看4楼
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