实验7
assume cs:codesgdata segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
codesg segment
start:mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov bx,0
mov si,0
mov di,0
mov cx,21
s0: mov al,
mov es:,al
mov ax,
mov es:,al
mov al,
mov es:,al
mov al,
mov es:,al
mov ax,54h
mov dx,56h
mov es:5h,ax
mov es:7h,dx
mov ax,0a8h
mov es:0ah,ax
mov ax,54h
mov dx,56h
div word ptr ds:0a8h
mov es:0dh,ax
add bx,4
add si,2
add di,16
loop s0
mov ax,4c00h
int 21h
codesg ends
end start
按照鱼老师的思路写的，想不出怎么简化了 本帖最后由 莫名其妙 于 2012-4-14 12:04 编辑
29.s0: mov al,
30.mov es:,al
31.mov ax,
32.mov es:,al
33.mov al,
34.mov es:,al
35.mov al,
36.mov es:,al
可以用mov ax,
mov es:,ax
mov ax,
mov es:,ax
一次保存两个数据
mov ax,54h
mov dx,56h
mov es:5h,ax
mov es:7h,dx
mov ax,0a8h
mov es:0ah,ax
mov ax,54h
mov dx,56h
div word ptr ds:0a8h
mov es:0dh,ax
1
mov ax,0a8h
mov es:0ah,ax
2
mov ax,54h
mov dx,56h
mov es:5h,ax
mov es:7h,dx
3
div word ptr ds:0a8h
mov es:0dh,ax
因为已经确定了每个数据存放的位置 可以提前吧人数存放进相应的单元 然后 在把总钱数 存进相应的ax dx中 然后直接进行除法
PS: 楼下有个 写实验7的 可以参考下!~
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