妹妹猪
发表于 2020-5-9 09:18:36
"""用while循环输出1~30的元组"""
n = 1
while n <= 30:
print((n, n+1, n+2))
n = n + 3
燕子的东先生啊
发表于 2020-5-9 13:27:12
学习一下
落叶飘飞
发表于 2020-5-10 09:41:44
i=1
while i<=30:
if i%3==0:
n=(i-2,i-1,i)
print(n)
i+=1
神秘小帅哥
发表于 2020-5-10 14:37:10
>>> x = 1
>>> while x< 30:
print((x,x+1,x+2))
x += 3
有谁懂
发表于 2020-5-11 10:52:23
i = 1
while i <= 30:
a = i
b = i + 1
c = i + 2
i += 3
print(tuple())
BXQXX
发表于 2020-5-11 11:15:11
>>> x = 1
>>> while x< 30:
print((x,x+1,x+2))
x += 3
琉璃琉璃
发表于 2020-5-12 00:05:54
x = 1
while x <= 30:
print((x,x+1,x+2))
x += 3
WD湿
发表于 2020-5-14 17:15:03
YY啦啦啦啦
ForPorsche
发表于 2020-5-18 19:29:52
i = 1
while i < 31:
print((i,i+1,i+2))
i += 3
笑叹,
发表于 2020-5-20 22:50:46
{:10_256:}
噗呲。
发表于 2020-5-21 10:17:48
感谢楼楼分享的练习题.赞赞赞!
0623009
发表于 2020-5-21 20:44:34
方法①
for i in range(1,29,3):
print((i,i+1,i+2))
方法②
i=1
while i <= 28:
print((i,i+1,i+2))
i+=3
遁天入地1412
发表于 2020-5-22 17:12:07
{:5_109:}
Commongg
发表于 2020-5-22 20:29:16
i=1
s=(i,i+1,i+2)
while i+2<=30
print(s)
i+=3
Commongg
发表于 2020-5-22 20:31:15
i=1
s=(i,i+1,i+2)
while i+2<=30
print(s)
i+=3
Commongg
发表于 2020-5-22 20:46:59
Commongg 发表于 2020-5-22 20:31
i=1
s=(i,i+1,i+2)
while i+2<=30
不对?
Commongg
发表于 2020-5-22 22:06:38
n=1
while n+2 <= 30:
print((n,n+1,n+2))
n += 3
ok
一定学好python
发表于 2020-5-25 15:45:30
'''x = 1
while x< 30:
a=(x,x+1,x+2)
print(tuple(a))
x += 3'''
zwhe
发表于 2020-5-26 15:50:09
{:10_304:}
噗呲。
发表于 2020-5-30 11:16:38
i = 3
while i <= 30:
print((i-2,i-1,i))
i += 3