"""用while循环输出1~30的元组"""
n = 1
while n <= 30:
print((n, n+1, n+2))
n = n + 3
学习一下
i=1
while i<=30:
if i%3==0:
n=(i-2,i-1,i)
print(n)
i+=1
>>> x = 1
>>> while x< 30:
print((x,x+1,x+2))
x += 3
i = 1
while i <= 30:
a = i
b = i + 1
c = i + 2
i += 3
print(tuple())
>>> x = 1
>>> while x< 30:
print((x,x+1,x+2))
x += 3
x = 1
while x <= 30:
print((x,x+1,x+2))
x += 3
YY啦啦啦啦
i = 1
while i < 31:
print((i,i+1,i+2))
i += 3
{:10_256:}
感谢楼楼分享的练习题.赞赞赞!
方法①
for i in range(1,29,3):
print((i,i+1,i+2))
方法②
i=1
while i <= 28:
print((i,i+1,i+2))
i+=3
{:5_109:}
i=1
s=(i,i+1,i+2)
while i+2<=30
print(s)
i+=3
i=1
s=(i,i+1,i+2)
while i+2<=30
print(s)
i+=3
Commongg 发表于 2020-5-22 20:31
i=1
s=(i,i+1,i+2)
while i+2<=30
不对?
n=1
while n+2 <= 30:
print((n,n+1,n+2))
n += 3
ok
'''x = 1
while x< 30:
a=(x,x+1,x+2)
print(tuple(a))
x += 3'''
{:10_304:}
i = 3
while i <= 30:
print((i-2,i-1,i))
i += 3