求检查代码
mima1 = r'''`!@#$%^&*()_+-=/*{}[]\|'";:/?,.<>'''mima2 = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
mima3 = '0123456789'
shuru = input("请输入需要判断的密码组合：")
changdu = len(shuru)
while (shuru.isspace() or changdu == 0):
shuru = input("空白字符无效请重新输入：")
changdu = len(shuru)
if changdu <=8 :
changdu_len = 1
elif 8 < changdu < 16 :
changdu_len = 2
else:
changdu_len = 3
anquan = 3
for temp in shuru:
if temp in mima1:
anquan += 1
break
for temp in shuru:
if temp in mima2:
anquan += 1
break
for temp in shuru:
if temp in mima3:
anquan += 1
break
while 1:
print("您输入得密码评级为：",end= " ")
if anquan == 1 or changdu == 1:
print("低")
elif anquan == 3 and changdu == 3 and (shuruin mima2):
print("高")
else:
print("中")
break
这个代码怎么总是显示密码是中我哪里出错了求大佬检查一下 你那个else可能要给条件 本帖最后由 Twilight6 于 2020-6-5 08:24 编辑
因为你中间的代码给 anquan = 3 赋值了 3你应该赋值 0 后面才能判断 如果你赋值 3 后面 if 条件应该是判断 anquan = 4 或anquan = 6
还有 下面if 条件 应该是判断长度的 changdu_len 而不是 changdu
你这边条件 ：shuruin mima2 意思是开头密码要字母吗? 可以删了
完整代码：
mima1 = r'''`!@#$%^&*()_+-=/*{}[]\|'";:/?,.<>'''
mima2 = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
mima3 = '0123456789'
shuru = input("请输入需要判断的密码组合：")
changdu = len(shuru)
while (shuru.isspace() or changdu == 0):
shuru = input("空白字符无效请重新输入：")
changdu = len(shuru)
if changdu <=8 :
changdu_len = 1
elif 8 < changdu < 16 :
changdu_len = 2
else:
changdu_len = 3
anquan = 0
for temp in shuru:
if temp in mima1:
anquan += 1
break
for temp in shuru:
if temp in mima2:
anquan += 1
break
for temp in shuru:
if temp in mima3:
anquan += 1
break
while 1:
print("您输入得密码评级为：",end= " ")
if anquan == 1 or changdu_len == 1:
print("低")
elif anquan == 3 and changdu_len == 3 :
print("高")
else:
print("中")
break
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