胡天赐啊 发表于 2020-6-29 10:00:00

计算器实现阶乘功能

这是我编的计算器：
from tkinter import *
from math import *

window = Tk()
window.title='计算器'
window.geometry('300x450')
f=Frame(window)
f.pack()
v=StringVar()

def clear():
    e.delete(0,END)
def calc():
    v.set(eval(e.get()))

def pow1():
    p=e.get()
    result=int(p)*int(p)
    v.set(result)
   
def factorial1():
    s = 1
    n=e.get()
    for i in range(1,n+1):
      s=s*i
    v.set(s)
   
def sqrt1():
    pass
   

e=Entry(f,text=v,width=8,font=('Arial',31))
e.grid(row=0,columnspan=4)
Button(f,text=1,width=2,command=lambda:e.insert(INSERT,'1'),font=('Arial',31)).grid(row=1,column=0)
Button(f,text=2,width=2,command=lambda:e.insert(INSERT,'2'),font=('Arial',31)).grid(row=1,column=1)
Button(f,text=3,width=2,command=lambda:e.insert(INSERT,'3'),font=('Arial',31)).grid(row=1,column=2)
Button(f,text='+',width=2,command=lambda:e.insert(INSERT,'+'),font=('Arial',31)).grid(row=1,column=3)
Button(f,text='4',width=2,command=lambda:e.insert(INSERT,'4'),font=('Arial',31)).grid(row=2,column=0)
Button(f,text='5',width=2,command=lambda:e.insert(INSERT,'5'),font=('Arial',31)).grid(row=2,column=1)
Button(f,text='6',width=2,command=lambda:e.insert(INSERT,'6'),font=('Arial',31)).grid(row=2,column=2)
Button(f,text='-',width=2,command=lambda:e.insert(INSERT,'-'),font=('Arial',31)).grid(row=2,column=3)
Button(f,text='7',width=2,command=lambda:e.insert(INSERT,'7'),font=('Arial',31)).grid(row=3,column=0)
Button(f,text='8',width=2,command=lambda:e.insert(INSERT,'8'),font=('Arial',31)).grid(row=3,column=1)
Button(f,text='9',width=2,command=lambda:e.insert(INSERT,'9'),font=('Arial',31)).grid(row=3,column=2)
Button(f,text='*',width=2,command=lambda:e.insert(INSERT,'*'),font=('Arial',31)).grid(row=3,column=3)
Button(f,text='0',width=2,command=lambda:e.insert(INSERT,'0'),font=('Arial',31)).grid(row=4,column=0)
Button(f,text='=',width=2,command=calc,font=('Arial',31)).grid(row=4,column=1)
Button(f,text='c',width=2,command=clear,font=('Arial',31)).grid(row=4,column=2)
Button(f,text='/',width=2,command=lambda:e.insert(INSERT,'/'),font=('Arial',31)).grid(row=4,column=3)
Button(f,text='p',width=2,command=pow1,font=('Arial',31)).grid(row=5,column=0)
Button(f,text='k',width=2,command=sqrt1,font=('Arial',31)).grid(row=5,column=1)
Button(f,text='j',width=2,command=factorial1,font=('Arial',31)).grid(row=5,column=2)
Button(f,text='.',width=2,command=lambda:e.insert(INSERT,'.'),font=('Arial',31)).grid(row=5,column=3)



def factorial1():
    s = 1
    n=e.get()
    for i in range(1,n+1):
      s=s*i
    v.set(s)
为啥实现阶乘的函数运行错误：TypeError: can only concatenate str (not "int") to str；
还有这个开方函数要怎么弄
   
def sqrt1():
   

永恒的蓝色梦想 发表于 2020-6-29 10:04:08

def factorial1():
    s = 1
    n=int(e.get())
    while n:
      s*=n
      n-=1
    v.set(s)

永恒的蓝色梦想 发表于 2020-6-29 10:06:04

def sqrt1():
    v.set(int(e.get())**0.5)

永恒的蓝色梦想 发表于 2020-6-29 10:06:36

满意请选最佳~{:10_297:}

Twilight6 发表于 2020-6-29 10:06:44



n=e.get()获取到的是字符串转为整型即可，还有你上次也是问这些的，问题解决了记得结账下

Twilight6 发表于 2020-6-29 10:07:46

永恒的蓝色梦想 发表于 2020-6-29 10:06
满意请选最佳~

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