请问我的缩进问题出在哪了？,Python交流,编程语言专区,鱼C论坛

磊之茶 发表于 2020-7-18 22:05:38

请问我的缩进问题出在哪了？

本帖最后由磊之茶于 2020-7-18 22:09 编辑

代码：
def sc(mb=None):
if mb==None:
   return None
c=mb.split('\n')
ln=0
relist={}
for i in c:
   col=0
   for a in i:
         relist[(ln,col)]=True if a ==' ' else False
         col+=1
   ln+=1
return relist

def panduan(mb={},lnd=[(0,0)],worn=[],win):
if type(mb) != dict or (0,0) in worn:
   return "I don't know!"
else:
   ln,col=lnd
   if lnd==win:
         return lnd
   d=(ln+1,col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   d=(ln-1,col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   d=(ln,col+1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   d=(ln,col-1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   else:
         lnd.pop()
         worn.append(d)
         panduan(mb,lnd,worn,win)
if __name__=='__main__':
d=input('请在下方输入这个迷宫的样子：（空格为没有）\n')
mu=sc(d)
for i in mu:
   g=i
d=panduan(mu,win=g)
if d=="I don't know!":
   print('你这是无解的迷宫！')
else:
   for i in d:
         mu=''
   for i in mu:
         print(mu,end='')
它说缩进有问题。但它到底哪里有缩进问题了？

磊之茶 发表于 2020-7-18 22:06:10

有谁能解决缩进问题？

wuqramy 发表于 2020-7-18 22:06:33

本帖最后由 wuqramy 于 2020-7-18 22:16 编辑

来看这一段：
def panduan(mb={},lnd=[(0,0)],worn=[],win):
if type(mb) != dict or (0,0) in worn:
   return "I don't know!"
else:
   ln,col=lnd
   if lnd==win:
         return lnd
   d=(ln+1,col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   d=(ln-1,col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   d=(ln,col+1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   d=(ln,col-1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   else:
         lnd.pop()
         worn.append(d)
         panduan(mb,lnd,worn,win)
问题1：黄色部分影响了elif的运行，分别要加一个Tab
问题2：这里它报错：
SyntaxError: non-default argument follows default argument
翻译：SyntaxError：非默认参数跟随默认参数
我们要把非默认参数（win）放在默认参数前面定义
正确代码，试一试：
def sc(mb=None):
if mb==None:
   return None
c=mb.split('\n')
ln=0
relist={}
for i in c:
   col=0
   for a in i:
         relist[(ln,col)]=True if a ==' ' else False
         col+=1
   ln+=1
return relist

def panduan(win,mb={},lnd=[(0,0)],worn=[]):
if type(mb) != dict or (0,0) in worn:
   return "I don't know!"
else:
   ln,col=lnd
   if lnd==win:
         return lnd
         d=(ln+1,col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
         d=(ln-1,col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
         d=(ln,col+1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
         d=(ln,col-1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   else:
         lnd.pop()
         worn.append(d)
         panduan(mb,lnd,worn,win)
if __name__=='__main__':
d=input('请在下方输入这个迷宫的样子：（空格为没有）\n')
mu=sc(d)
for i in mu:
   g=i
d=panduan(mu,win=g)
if d=="I don't know!":
   print('你这是无解的迷宫！')
else:
   for i in d:
         mu=''
   for i in mu:
         print(mu,end='')
如果没有实现目的，elif这个错误用if分开写：
def sc(mb=None):
if mb == None:
   return None
c = mb.split('\n')
ln = 0
relist = {}
for i in c:
   col = 0
   for a in i:
         relist[(ln, col)] = True if a == ' ' else False
         col += 1
   ln += 1
return relist

def panduan(mb={}, lnd=[(0, 0)], worn=[], win):
if type(mb) != dict or (0, 0) in worn:
   return "I don't know!"
else:
   ln, col = lnd
   if lnd == win:
         return lnd
   d = (ln + 1, col)
   if d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb, lnd, worn, win)
   d = (ln - 1, col)
   if d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb, lnd, worn, win)

   d = (ln, col + 1)
   if d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb, lnd, worn, win)
   d = (ln, col - 1)
   if d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb, lnd, worn, win)
   else:
         lnd.pop()
         worn.append(d)
         panduan(mb, lnd, worn, win)
if __name__ == '__main__':
d = input('请在下方输入这个迷宫的样子：（空格为没有）\n')
mu = sc(d)
for i in mu:
   g = i
d = panduan(mu, win=g)
if d == "I don't know!":
   print('你这是无解的迷宫！')
else:
   for i in d:
         mu = ''
   for i in mu:
         print(mu, end='')

1q23w31 发表于 2020-7-18 22:08:27

本帖最后由 1q23w31 于 2020-7-18 22:12 编辑

def sc(mb=None):
if mb==None:
   return None
c=mb.split('\n')
ln=0
relist={}
for i in c:
   col=0
   for a in i:
         relist[(ln,col)]=True if a ==' ' else False
         col+=1
   ln+=1
return relist

def panduan(mb={},lnd=[(0,0)],worn=[],win):
if type(mb) != dict or (0,0) in worn:
   return "I don't know!"
else:
   ln,col=lnd
   if lnd==win:
         return lnd
   d=(ln+1,col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   d=(ln-1,col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   d=(ln,col+1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   d=(ln,col-1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb,lnd,worn,win)
   else:
         lnd.pop()
         worn.append(d)
         panduan(mb,lnd,worn,win)
if __name__=='__main__':
d=input('请在下方输入这个迷宫的样子：（空格为没有）\n')
mu=sc(d)
for i in mu:
   g=i
d=panduan(mu,win=g)
if d=="I don't know!":
   print('你这是无解的迷宫！')
else:
   for i in d:
         mu=''
   for i in mu:
         print(mu,end='')

磊之茶 发表于 2020-7-18 22:16:28

Twilight6 发表于 2020-7-18 22:12
代码中的win 是哪个函数？代码有很多地方是错的唉，只能帮你改这么多了，我也不懂正确与否，不过运行 ...

win不是一个函数，是一个参数{:10_277:}

Twilight6 发表于 2020-7-18 22:18:39

磊之茶发表于 2020-7-18 22:16
win不是一个函数，是一个参数

噗的确是怪我没认真，改完了你重新看看吧，参数没设置默认值的不能放在设置默认值的后面

永恒的蓝色梦想 发表于 2020-7-18 22:20:09

磊之茶发表于 2020-7-18 22:16
win不是一个函数，是一个参数

你这串代码根本不能运行，d = input('请在下方输入这个迷宫的样子：（空格为没有）\n')input 只会读取一行

永恒的蓝色梦想 发表于 2020-7-18 22:21:02

磊之茶发表于 2020-7-18 22:16
win不是一个函数，是一个参数

你是不是想用关键字参数啊{:10_277:}def sc(mb=None):
if mb == None:
   return None
c = mb.split('\n')
ln = 0
relist = {}
for i in c:
   col = 0
   for a in i:
         relist[(ln, col)] = a == ' '
         col += 1
   ln += 1
return relist

def panduan(mb={}, lnd=[(0, 0)], worn=[], *, win):
if type(mb) != dict or (0, 0) in worn:
   return "I don't know!"
else:
   ln, col = lnd
   if lnd == win:
         return lnd
   d = (ln+1, col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb, lnd, worn, win)
   d = (ln-1, col)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb, lnd, worn, win)
   d = (ln, col+1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb, lnd, worn, win)
   d = (ln, col-1)
   elif d not in lnd and d not in worn and mb:
         lnd.append(d)
         panduan(mb, lnd, worn, win)
   else:
         lnd.pop()
         worn.append(d)
         panduan(mb, lnd, worn, win)

if __name__ == '__main__':
d = input('请在下方输入这个迷宫的样子：（空格为没有）\n')
mu = sc(d)
for i in mu:
   g = i
d = panduan(mu, win=g)
if d == "I don't know!":
   print('你这是无解的迷宫！')
else:
   for i in d:
         mu = ''
   for i in mu:
         print(mu, end='')

磊之茶 发表于 2020-7-20 09:17:54

永恒的蓝色梦想发表于 2020-7-18 22:21
你是不是想用关键字参数啊

没错

nahongyan1997 发表于 2020-7-21 11:54:04

研究了半天才发现你打算用递归。{:10_277:}

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请问我的缩进问题出在哪了？