课后作业~~35
如图,1.为什么我把print(count1)去掉count1返回的是0,改成return count1 也是返回的0
2,open(i,‘rb‘)打开.py类型的文件不是可以用'r'的形式,为什么这儿要用'rb'不然就会报错UnicodeDecodeError: 'gbk' codec can't decode byte 0xa5 in position 22: illegal multibyte sequence
from easygui import *
import os
def search_file(path):
os.chdir(path)
for each_file in os.listdir(os.curdir):
(file_name,extend) = os.path.splitext(each_file)
if extend == '.py':
py_file.append(os.getcwd()+os.sep+each_file)
if os.path.isdir(each_file):
search_file(each_file)
os.chdir(os.pardir)
py_file = []
search_path = diropenbox()
search_file(search_path)
def count_line(files,count1):
for i in files:
f = open(i,'rb')
for each_line in f:
count1 += 1
print(count1)
count1 = 0
count_line(py_file,count1)
编码错误,rb 是二进制打开读取,你应该试试 utf-8 编码:
from easygui import *
import os
def search_file(path):
os.chdir(path)
for each_file in os.listdir(os.curdir):
(file_name,extend) = os.path.splitext(each_file)
if extend == '.py':
py_file.append(os.getcwd()+os.sep+each_file)
if os.path.isdir(each_file):
search_file(each_file)
os.chdir(os.pardir)
py_file = []
search_path = diropenbox()
search_file(search_path)
def count_line(files,count1):
for i in files:
f = open(i,encoding='utf-8')
for each_line in f:
count1 += 1
print(count1)
count1 = 0
count_line(py_file,count1)
Twilight6 发表于 2020-7-22 10:32
编码错误,rb 是二进制打开读取,你应该试试 utf-8 编码:
直接f = open(i)为什么不行? 这个utf-8还没遇到过,我只是想单纯的读取行数,用二进制打开读取的行数会不会错? def花 发表于 2020-7-22 10:37
直接f = open(i)为什么不行? 这个utf-8还没遇到过,我只是想单纯的读取行数,用二进制打开读取的行数会 ...
Python 默认是 gbk 编码,如果文本是 utf-8 编码以 Python 默认打开就会报错了,因为 gbk 和 utf-8 编码字节不同
以二进制打开的文件你确定你能看得懂吗....
Twilight6 发表于 2020-7-22 10:38
Python 默认是 gbk 编码,如果文本是 utf-8 编码以 Python 默认打开就会报错了,因为 gbk 和 utf-8 ...
QAQ可是我在idle上就可以实现f = open(i),这又是为什么,我懵了 除了楼上所提出的 bug 外,您的代码因为第 11 行的执行与导致第 12 行永远无法被执行,
所以无法改变您的工作目录。
我修改了您的代码以实现您想要的功能:
from easygui import *
import os
def search_file(path):
for root,file_dir,file_list in os.walk(path):
for each_file in file_list:
if os.path.splitext(each_file) == '.py':
py_file.append(os.path.join(root,each_file))
py_file = []
search_path = diropenbox()
search_file(search_path)
def count_line(files,count1):
for i in files:
f = open(i,'rb')
for each_line in f:
count1 += 1
print(f'您一共写了{count1}行代码。)
count1 = 0
count_line(py_file,count1)
如果您对我的答案感到满意,请设置最佳答案! nahongyan1997 发表于 2020-7-22 10:52
除了楼上所提出的 bug 外,您的代码因为第 11 行的执行与导致第 12 行永远无法被执行,
所以无法改变您的 ...
大佬,你的方法比较高级QAQ,不过我执行出来所有文件也找齐了呀
不过改print(count1)为return count1 ,count1为什么会一直返回0 def花 发表于 2020-7-22 11:06
大佬,你的方法比较高级QAQ,不过我执行出来所有文件也找齐了呀
不过改print(count1)为return count1...
from easygui import *
import os
def search_file(path):
for root,file_dir,file_list in os.walk(path):
for each_file in file_list:
if os.path.splitext(each_file) == '.py':
py_file.append(os.path.join(root,each_file))
py_file = []
search_path = diropenbox()
search_file(search_path)
def count_line(files,count1):
for i in files:
f = open(i,'rb')
for each_line in f:
count1 += 1
return f'您一共写了{count1}行代码。'
count1 = 0
print(count_line(py_file,count1))
你可能是把 print 写成了这样:
from easygui import *
import os
def search_file(path):
for root,file_dir,file_list in os.walk(path):
for each_file in file_list:
if os.path.splitext(each_file) == '.py':
py_file.append(os.path.join(root,each_file))
py_file = []
search_path = diropenbox()
search_file(search_path)
def count_line(files,count1):
for i in files:
f = open(i,'rb')
for each_line in f:
count1 += 1
return f'您一共写了{count1}行代码。'
count1 = 0
count_line(py_file,count1)
print(count1)
为什么coun1会返回0QAQ nahongyan1997 发表于 2020-7-22 11:12
你可能是把 print 写成了这样:
我是这么写的
from easygui import *
import os
def search_file(path):
os.chdir(path)
for each_file in os.listdir(os.curdir):
(file_name,extend) = os.path.splitext(each_file)
if extend == '.py':
py_file.append(os.getcwd()+os.sep+each_file)
if os.path.isdir(each_file):
search_file(each_file)
os.chdir(os.pardir)
py_file = []
search_path = diropenbox('请选择你的代码库')
search_file(search_path)
def count_line(files,count1):
for i in files:
f = open(i,encoding='utf-8')
for each_line in f:
count1 += 1
return count1
count1 = 0
count_line(py_file,count1)
file_number = len(py_file)
lack_row = 100000 - count1
percentage = str(count1/100000*100)[:4] + '%'
msg = '您目前共累计编写了%d行代码,完成进度:%s\n离10万行代码还差%d行,请继续努力!' % (count1,percentage,lack_row)
title = '显示文件内容'
text = '【.py】源文件%d个,源代码%d行' % (file_number,count1)
textbox(msg,title,text)
def花 发表于 2020-7-22 11:14
我是这么写的
from easygui import *
import os
def search_file(path):
os.chdir(path)
for each_file in os.listdir(os.curdir):
(file_name,extend) = os.path.splitext(each_file)
if extend == '.py':
py_file.append(os.getcwd()+os.sep+each_file)
# 如果这条 if 语句为真,你的程序 100% 会报错!
if os.path.isdir(each_file):
search_file(each_file)
os.chdir(os.pardir)
py_file = []
search_path = diropenbox('请选择你的代码库')
search_file(search_path)
def count_line(files,count1):
for i in files:
f = open(i,encoding='utf-8')
for each_line in f:
count1 += 1
return count1
count1 = 0
# 这里需要对 count1 变量进行重新赋值!
count1 = count_line(py_file,count1)
file_number = len(py_file)
lack_row = 100000 - count1
percentage = str(count1/100000*100)[:4] + '%'
msg = '您目前共累计编写了%d行代码,完成进度:%s\n离10万行代码还差%d行,请继续努力!' % (count1,percentage,lack_row)
title = '显示文件内容'
text = '【.py】源文件%d个,源代码%d行' % (file_number,count1)
textbox(msg,title,text)
如果您对我的答案感到满意,请设置最佳答案!谢谢
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