论坛 › Python交流 › 日期转化星期，我的程序哪里不对呢

还不够好 发表于 2020-10-28 07:09:39

日期转化星期，我的程序哪里不对呢

year = int(input())
m = int(input())
q = int(input())

if m == 1:
    m = 13
    year -= 1
elif m == 2:
    m = 14
    year -= 1
   
j = year / 100
k = year % 100

h =(q + (26 * (m + 1))/10 + k + 0.25 * (k + j) + 5 * j) % 7

if h == 0:
    result = "星期六"
elif h == 1:
    result = "星期天"
elif h == 2:
    result = "星期一"
elif h == 3:
    result = "星期二"
elif h == 4:
    result = "星期三"
elif h == 5:
    result = "星期四"
elif h == 6:
    result = "星期五"
print(h)
print(year,"年",m,"月",q,"日是",result)

wp231957 发表于 2020-10-28 07:39:04

这里不应该有小数，把所有的除号换成整除号试一下

笨鸟学飞 发表于 2020-10-28 09:04:12

h =(q + (26 * (m + 1))/10 + k + 0.25 * (k + j) + 5 * j) % 7

#关键在这行代码，h为初次调用，h的类型看右边赋值情况
#你看(26 * (m + 1))/10，例如m=13，则计算结果是小数
#那其他代码不用看了，括号内计算结果一定是小数。小数除以7求余数也是小数
#小数用判断来比较。。。能不出问题么

一只胖麻圆 发表于 2020-10-28 09:51:11

import math
year = int(input("请输入年份:"))
m = int(input("请输入月份:"))
q = int(input("请输入日期:"))

if m == 1:
    m = 13
    year -= 1
elif m == 2:
    m = 14
    year -= 1

j = year / 100
k = year % 100

h = int((q + (26 * (m + 1)) % 10 + k + 0.25 * (k + j) + 5 * j) % 7)


if h == 0:
    result = "星期六"
elif h == 1:
    result = "星期天"
elif h == 2:
    result = "星期一"
elif h == 3:
    result = "星期二"
elif h == 4:
    result = "星期三"
elif h == 5:
    result = "星期四"
elif h == 6:
    result = "星期五"
print(h)
print(year, "年", m, "月", q, "日是", result)

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