求解，才开始学，让我能看懂
SEND+MORE=MONEY这道题用python怎么写？简单粗暴的那种解法。 你想表达什么 就用个最简单最粗暴的写法。from functools import reduce
fun = lambda x, y: 10 * x + y
M = 1
for S in range(8, 10):
for E in set(range(10)) - {S, M}:
for N in set(range(10)) - {S, E, M}:
for D in set(range(10)) - {S, E, N, M}:
for O in set(range(10)) - {S, E, N, D, M}:
for R in set(range(10)) - {S, E, N, D, O, M}:
for Y in set(range(10)) - {S, E, N, D, O, R, M}:
SEND = reduce(fun, (S, E, N, D))
MORE = reduce(fun, (M, O, R, E))
MONEY = reduce(fun, (M, O, N, E, Y))
ifSEND + MORE == MONEY:
print('%d + %d = %d'%(SEND, MORE, MONEY))
exit()
9567 + 1085 = 10652
注：M是进位得到的只能是1 小可爱. 发表于 2020-11-2 23:19
你想表达什么
才学了一个月python，很容易看不懂，所以想找个简单的代码 @0.0@sos 发表于 2020-11-3 20:07
才学了一个月python，很容易看不懂，所以想找个简单的代码
可这个问题本身就不简单 我就注释一下上面那位的代码吧：
from functools import reduce
fun = lambda x, y: 10 * x + y
M = 1 # 由于两数相加最多只能进1位
for S in range(8, 10): # S + 1 +1/0 >9 即 s可以是 8或9；这里我们用集合形式 set() 写出来。集合没有重复元素，E不可能与S，M重复，故减去SM
for E in set(range(10)) - {S, M}:
for N in set(range(10)) - {S, E, M}:
for D in set(range(10)) - {S, E, N, M}:
for O in set(range(10)) - {S, E, N, D, M}:
for R in set(range(10)) - {S, E, N, D, O, M}:
for Y in set(range(10)) - {S, E, N, D, O, R, M}:
SEND = reduce(fun, (S, E, N, D)) # 这么看就简单了，其实就等价于 SEND = S*1000 + E*100 + N*10 + D
MORE = reduce(fun, (M, O, R, E)) # 同理
MONEY = reduce(fun, (M, O, N, E, Y))
ifSEND + MORE == MONEY: # 最后循环判断了下而已
print('%d + %d = %d'%(SEND, MORE, MONEY))
exit()
页:
[1]