19节练习
题目为 统计出传入字符串参数的英文字母、空格、数字和其它字符的个数。我的解答：
words = input('input your words here: ')
def azx(*words):
letters = 0
nums = 0
blanks = 0
others = 0
for each in words:
if each.isalpha() == True:
letters += 1
return letters
elif each.isdigit() == True:
nums += 1
return nums
elif each.isspace() == True:
blanks += 1
return blanks
else:
others += 1
return others
print('字符串共有：英文字母','%d' % letters,'个，数字','%d' % nums,'个,空格','%d' % blanks,'个，其他字符','%d' % others,'个。')
我能问一下大佬们我这个错在哪里了吗？学艺不精，勿怪！谢谢大佬们了！ 帮你改了一下
words = input('input your words here: ')
def azx(words):
letters = 0
nums = 0
blanks = 0
others = 0
for each in words:
if each.isalpha() == True:
letters += 1
elif each.isdigit() == True:
nums += 1
elif each.isspace() == True:
blanks += 1
else:
others += 1
return letters, nums,blanks, others
print('字符串共有：英文字母%d个，数字%d个,空格%d个，其他字符%d'%azx(words))
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