爱心代码问题
在网上搜到的c爱心代码，我想实现一下在心形里面输出人名#include <stdio.h>
int main() {
for (float y = 1.5f; y > -1.5f; y -= 0.1f) {
for (float x = -1.5f; x < 1.5f; x += 0.05f) {
float z = x * x + y * y - 1;
float f = z * z * z - x * x * y * y * y;
putchar(f <= 0.0f ? ".:-=+*#%@"[(int)(f * -8.0f)] : ' ');
}
putchar('\n');
}
}
谢谢！ #include <stdio.h>
#include <math.h>
#include <stdlib.h>
#define I 20
#define R 340
int main()
{
int i, j, e;
int a;
long time;
system("title 小甲鱼C语言学习天地");
for (i = 1, a = I; i<I / 2; i++, a--)
{
for (j = (int)(I - sqrt(I*I - (a - i)*(a - i))); j>0; j--)
printf(" ");
for (e = 1; e <= 2 * sqrt(I*I - (a - i)*(a - i)); e++)
printf("\3");
for (j = (int)
(2 * (I - sqrt(I*I - (a - i)*(a - i)))); j>0; j--)
printf(" ");
for (e = 1; e <= 2 * sqrt(I*I - (a - i)*(a - i)); e++)
printf("\3");
printf("\n");
}
for (i = 1; i<80; i++)
{
if (i == 25)
{
printf(" 我爱小甲鱼(bbs.fishc.com) ");
i += 30;
}
printf("\3");
}
printf("\n");
for (i = 1; i <= R / 2; i++)
{
if (i % 2 || i % 3)
continue;
for (j = (int)(R - sqrt(R*R - i*i)); j>0; j--)
printf(" ");
for (e = 1; e <= 2 * (sqrt(R*R - i*i) - (R - 2 * I)); e++)
printf("\3");
printf("\n");
}
for (; ; )
{
system("color a");
for (time = 0; time<99999999; time++); system("color b");
for (time = 0; time<99999999; time++); system("color c");
for (time = 0; time<99999999; time++); system("color d");
for (time = 0; time<99999999; time++); system("color e");
for (time = 0; time<99999999; time++); system("color f");
for (time = 0; time<99999999; time++);
system("color 0"); for (time = 0; time<99999999; time++);
system("color 1"); for (time = 0; time<99999999; time++);
system("color 2"); for (time = 0; time<99999999; time++);
system("color 3"); for (time = 0; time<99999999; time++);
system("color 4");
for (time = 0; time<99999999; time++); system("color 5");
for (time = 0; time<99999999; time++); system("color 6");
for (time = 0; time<99999999; time++); system("color 7");
for (time = 0; time<99999999; time++); system("color 8");
for (time = 0; time<99999999; time++); system("color 9");
for (time = 0; time<99999999; time++); system("color ab");
for (time = 0; time<99999999; time++); system("color ac");
for (time = 0; time<99999999; time++); system("color ad");
for (time = 0; time<99999999; time++); system("color ae");
for (time = 0; time<99999999; time++); system("color af");
for (time = 0; time<99999999; time++);
}
return 0;
}
页:
[1]