python 6课习题求阶梯,百思不得其解
本帖最后由 huyanmin 于 2020-12-22 17:52 编辑x = 7
n=1
flag = 0
while n<=100:
if (x%2== 1) and (x%3== 2) and (x%4 == 3) and (x%5 == 4) and (x%6 == 5):
flag = 1
else:
x = 7*n
n+=1 #修改此处缩进到else里，代码就不能正常执行，都是全局变量，怎么会不能执行，晕啊
if flag == 1:
print('阶梯数是：', x)
else:
print('在程序限定的范围内找不到答案！')
#原代码
x = 7
i = 1
flag = 0
while i <= 100:
if (x%2 == 1) and (x%3 == 2) and (x%5 == 4) and (x%6==5):
flag = 1
else:
x = 7 * (i+1) # 根据题意，x一定是7的整数倍，所以每次乘以7
i += 1#此处鱼else拉齐，
if flag == 1:
print('阶梯数是：', x)
else:
print('在程序限定的范围内找不到答案！') 本帖最后由 jackz007 于 2020-12-22 17:59 编辑
while n<=100:
if (x%2== 1) and (x%3== 2) and (x%4 == 3) and (x%5 == 4) and (x%6 == 5):
flag = 1
else:
x = 7*n
n+=1 #此处缩进到else里，就意味着只有 x 不满足条件的时候才会被执行，一旦满足，n 在循环中就再也没有机会被改变了，这样，就会成为死循环。
代码这么改，逻辑会更加简洁
flag = 0
for x in range(7 , 701 , 7):
if (x % 2 == 1) and (x % 3 == 2) and (x % 5 == 4) and (x % 6 == 5):
print('阶梯数是：', x)
flag = 1
if flag == 0:
print('在程序限定的范围内找不到答案！')
页:
[1]