C++递增运算符重载
#include<iostream>using namespace std;
class MyInteger{
friend ostream& operator<<(ostream& cout, MyInteger myint);
private:
int m_num;
public:
//构造函数
MyInteger()
{
m_num = 0;
}
//前置++操作
MyInteger& operator++()
{
m_num++;
return *this;
}
//后置++操作
MyInteger operator++(int)
{
MyInteger temp = *this;
m_num++;
return temp;
}
};
ostream& operator<<(ostream& cout, MyInteger myint)
{
cout << "myint.m_num = " << myint.m_num << endl;
return cout;
}
int main() {
MyInteger myint;
cout << ++myint << endl;
cout << myint << endl;
cout << myint++ << endl;
cout << myint << endl;
system("pause");
return 0;
}
代码如上所示
求问在cout输出那块编译器是怎么知道++在对象前就调用第一个++重载函数，++在对象后就调用第二个++重载函数的 c++规定的就是
operator++ () 是前置 ++重载， operator++(int) 是后置 ++ 重载。
++在对象前就调用 ++()，++在对象后就调用 ++(int)
这很明白啊。
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