为啥这个函数返回值是None呢，明明return(answer)了啊（用递归编写十进制转二进制）
def ten_two(num, list1 = [], judge = 1):if num < 0:
judge = 0
num = abs(num)
if num // 2 == 0:
list1.append('1')
list1.append('b')
list1.append('0')
if judge == 0:
list1.append('-')
answer = str()
while list1:
answer += str(list1.pop())
print(answer)
return(answer)
else:
rem = num % 2
num = num // 2
list1.append(rem)
ten_two(num, list1, judge)
num = int(input("请输入要转换的数字："))
print(ten_two(num))
还请大佬们帮我看看，谢谢辽！！！ 第二十行少打个return
def ten_two(num, list1 = [], judge = 1):
if num < 0:
judge = 0
num = abs(num)
elif num // 2 == 0:
list1.append('1')
list1.append('b')
list1.append('0')
if judge == 0:
list1.append('-')
answer = str()
while list1:
answer += str(list1.pop())
return answer
else:
rem = num % 2
num = num // 2
list1.append(rem)
return ten_two(num, list1, judge)
num = int(input("请输入要转换的数字："))
print(ten_two(num)) 第十七行的rem是干什么用的 peipur 发表于 2021-2-11 15:44
第十七行的rem是干什么用的
就是储存单次求余的结果鸭 逃兵 发表于 2021-2-11 11:29
第二十行少打个return
感谢哈！
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