如何判断是否到了次日
假如规定我在此时此刻的操作次数已经到达了上限，只有在次日0时0分0秒后才可继续操作或重新操作，如何判断是否到了次日。 本帖最后由 青出于蓝 于 2021-7-12 10:44 编辑time.strftime()
import time
c=time.strftime("%Y-%m-%d %H:%M:%S", time.localtime())[:10]#获取当天日期
while True:
iftime.strftime("%Y-%m-%d %H:%M:%S", time.localtime())[:10]!=c:
print(‘已经到了次日’)
欢迎追问
问题已经解决请设置最佳 >>> import time
>>> time_now = time.localtime(time.time())
>>> time_now
time.struct_time(tm_year=2021, tm_mon=7, tm_mday=11, tm_hour=16, tm_min=9, tm_sec=7, tm_wday=6, tm_yday=192, tm_isdst=0)
>>> time_now.tm_year
2021
>>> time_now.tm_mon
7
>>> time_now.tm_mday
11
>>> 请给出代码示例 永恒的蓝色梦想 发表于 2021-7-11 16:14
请给出代码示例
比如集五福活动，规定单日内最高只能获取福卡10张，若想继续集五福，则需要等到次日0时0分0秒后。
# coding:utf-8
"""
集五福，迎新春
"""
import random
from datetime import datetime
class Chances(object):
list_chance = []
def __init__(self):
for i in range(0, 90):
self.list_chance.append(0)
for i in range(0, 5):
self.list_chance.append(1)
for i in range(0, 3):
self.list_chance.append(2)
self.list_chance.append(3)
self.list_chance.append(4)
class Blessings(Chances):
# now = datetime.now()
cards = 0
money = 0
_blessings = 0
happy = {
"1": {"name": "富强福", "num": 0},
"2": {"name": "和谐福", "num": 0},
"3": {"name": "友善福", "num": 0},
"4": {"name": "爱国福", "num": 0},
"5": {"name": "敬业福", "num": 0}
}
def draw(self, start):
if isinstance(start, str):
number = random.randint(1, 5)
for k, v in self.happy.items():
if str(number) == k:
v["num"] = v["num"] + 1
self.cards += 1
print("获取到: {}".format(v["name"]))
# 规定每天获取到的福字卡片总数不得超过十张
def check_blessings(self):
if self.cards > 9:
print('=' * 20)
raise Exception('每日最多可获取{}张福'.format(self.cards))
def show(self):
print("当前拥有的福:")
for k, v in self.happy.items():
print(v["name"], ":", v["num"])
def service_list(self):
service_list = {
1: '按下<Enter>键集五福',
2: '按下<s>键查看获取福字',
3: '按下<c>合成五福',
4: '按下<d>抽红包',
5: '按下<q>退出'
}
for k, v in service_list.items():
print(v)
def cheak(self):
for k, v in self.happy.items():
if v['num'] > 0:
flag = True
else:
flag = False
break
return flag
def collect(self):
if self.cheak():
self._blessings += 1
print('当前合成{}张五福'.format(self._blessings))
for k, v in self.happy.items():
v['num'] -= 1
else:
print('当前合成{}张五福'.format(self._blessings))
for k, v in self.happy.items():
if v['num'] == 0:
print('缺少{}'.format(v['name']))
print('你的福不足！')
print('=' * 20)
def draw_cash(self):
if self._blessings > 0:
money_flag = random.choice(self.list_chance)
if money_flag == 0:
_money = random.randint(1, 5)
elif money_flag == 1:
_money = random.randint(1000, 1999)
elif money_flag == 2:
_money = random.randint(2000, 4999)
elif money_flag == 3:
_money = random.randint(5000, 9999)
elif money_flag == 4:
_money = random.randint(10000, 20000)
print('抽中红包金额{}'.format(_money))
self.money += _money
print('红包总金额{}'.format(self.money))
self._blessings -= 1
else:
print('五福不足！')
print('=' * 20)
def run(self):
while True:
self.service_list()
start = input("请选择：")
if start == '':
if self.cards < 10:
self.draw(start)
else:
try:
self.check_blessings()
except Exception as e:
print(e)
print('=' * 20)
elif start == 's':
self.show()
print('=' * 20)
elif start == 'c':
print('=' * 20)
self.collect()
elif start == 'q':
print('感谢使用，再见！')
print('=' * 20)
break
elif start == 'd':
print('=' * 20)
self.draw_cash()
else:
print('输入有误，重新输入！')
print('=' * 20)
if __name__ == '__main__':
b = Blessings()
b.run()
# print(b.now)
datetime, 然后用时间戳的等于(不等于)判断即可
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