5_8的一种解法
assume cs:codecode segment
mov bx,0 ;init offset address value
mov dx,0 ;init temp
mov cx,6
mov ax,0ffffh
mov ds,ax
mov ax,0200h
mov es,ax
s: mov dx,ds: ;for temp save
mov es:,dx
add bx,2
loop s
mov ax,4c00h
int 21h
code ends
end
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