小甲鱼20课课后作业问题,Python交流,技术交流,鱼C论坛

甜蜜难在 发表于 2022-1-7 14:05:07

小甲鱼20课课后作业问题

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qKWGc'''
length = len(a)
list = []
for i in range(length):
if a == '\n':
   continue
if a.islower():
   if a.isupper() and a.islower():
         if a.isupper() and a.islower():
            list.append(a)
            i += 1
print(list)

根据20课课后第二题的要求，我写了如上代码，我是利用切片的方法进行判断。假如i是小写，那么判断它前面三个字符和后面三个字符范围内的字符是否是大写，由此来得出密码，但是当我执行了之后，结果显示如下：

['u', 'i', 'l', 'o', 'v', 'e', 'f', 'i', 's', 'd', 'h', 'c']

与小甲鱼老师的答案比较的话多了一个u和d字符。思考了很久都不知道是怎么回事，请问有大神能解答一下吗。？小白不胜感激。

AdiosSpike 发表于 2022-1-7 18:10:15

我还没学到{:10_269:}

傻眼貓咪 发表于 2022-1-7 20:50:27

islower() 或 isupper() 最好一个一个比较，否则不准确，比如：
a = """
AASDFFF
HDTD
#$%^&**@@@
"""

b = "ABC AABBSS JKHK"

print(a.isupper()) # True
print(b.isupper()) # True可以看出以上结果，是也 True 不是也 True 这不是我们想要的，我的代码为：
# 因为字符串太长，所以另外存放在 text.txt 中

def isValid(s: str):

# 判断前第四个字符、后第四个字符、和中间字符是否都是小写
# 如：x _ _ _ x _ _ _ x
if not (s.islower() and s[-1].islower() and s.islower()): return False

# 判断前三个字符串和后三个字符串是否是大写
# 如：_ x x x _ x x x _
for i in s+s:
   if not i.isupper():
         return False

# 判断字符串是否有 9 个字符
return len(s) == 9

f = open("text.txt", "r")
text = f.read()

length = len(text)
res = []

for i in range(length-4):
if(isValid(text)):
   res.append(text)

print(''.join(res))

甜蜜难在 发表于 2022-1-8 16:26:50

傻眼貓咪发表于 2022-1-7 20:50
islower() 或 isupper() 最好一个一个比较，否则不准确，比如：
可以看出以上结果，是也 True 不是也 True ...

但是我也是按照这个思路来判断的啊。先判断中间字母是否小写，然后再判断前面三位和后面三位是否为大写，再判断前第四位和后第四位是否为小写。而且在小甲鱼提供的字符串里面是没有字符的。所以还是不太明白为什么我执行出来会多两个字母。当然您的方法也是正确的。

傻眼貓咪 发表于 2022-1-8 16:52:41

甜蜜难在发表于 2022-1-8 16:26
但是我也是按照这个思路来判断的啊。先判断中间字母是否小写，然后再判断前面三位和后面三位是否为大写， ...

length = len(a)
list = []
for i in range(length):
if a == '\n':
   continue
if a.islower():
   if a.isupper() and a.islower():
         if a.isupper() and a.islower():
            list.append(a)
            print(a) # 试试加多这一行代码你就明白了
            i += 1
print(list)

甜蜜难在 发表于 2022-1-8 16:56:10

傻眼貓咪发表于 2022-1-8 16:52

我理解了，刚刚使用调试功能，找到了第一个u字母的索引位置，然后查看了前面和后面的字符，发现前面的三个字符中包含了一个\n字符，然后判断也是Ture，所以是这个原因导致了多了字母。万分感谢。！

甜蜜难在 发表于 2022-1-8 17:40:00

我坚持用我的方法，然后经过我的倔强之后，通过方法先将字符串的'\n'全部删除掉，然后组成新字符串，然后再用我的思路来判断，现在结果终于和小甲鱼一样了。
a = []
with open(r"d:\Users\zhongsong\Desktop\string2.txt", "r") as f1:
for each in f1.readlines():
   if each is not None:
         a.append(each.strip("\n"))
f1.close()
b = (''.join(a))
# print(b)
length = len(b)
list = []
for i in range(length):
if b == '\n':
   continue
if b.islower():
   if b.isupper() and b.islower():
         if b.isupper() and b.islower():
            list.append(b)
            i += 1
print(''.join(list))

总结下来，就是小甲鱼老师讲课的时候没有特别仔细，就像这种字符串里面有换行符的情况下也会判断为True，看来这个是个要点。需要大家规避一下。

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小甲鱼20课课后作业问题