自动密码生成器v2.9.5
本帖最后由 shiyouroc 于 2022-11-26 13:53 编辑问题；
1.空格太多。
2，函数名是乱的，因为我英文不好。
解决；
1.加注释
2.去bug
# coding=utf-8
#!/usr/bin/python
# Write Python 3 code in this online editor and run it.
from random import randint
from sys import exit
yes = 1#设全局变量
ye = 1#设全局变量
xiao=['a','b','c','d','e','f',
'g','h','i','j','k','l',
'm','n','o','q','p','r',
't','s','u','v','w','x','y',
'z']
da =
def three_engling():
global yes#把全局变量转为局部变量
global ye #把全局变量转为局部变量
yes = input("是1退0")
ye = yes.isdigit() #判断字符串是否是数字，是ture 否flase
print(ye) #打印判断结果
def dcdy():
global yes
ffff = len(yes)
if ffff > 2:
print('请勿非法输入。')
cc()
def tt():
global yes #把全局变量转为局部变量
global ye #把全局变量转为局部变量
while ye == False:
print('请勿非法输入。')
yes = input("是1退0")
ye = yes.isdigit()
if ye == False:
cc()
else:
break
def dd():
global yes #把全局变量转为局部变量
yes = int(yes)
if yes > 1:
print('请勿非法输入。')
cc()
if yes ==0:
exit(0)
def sc():
y=randint(0,2) #选前三个字母的其中一个字母为小写
if y==0: #如果为零第一个字母为小写
d=randint(0,25)
one=xiao
else:
d = randint(0,25)
one = da
if y==1:#如果为1第一个字母为小写
q= randint(0,25)
two = xiao
else:
q = randint(0,25)
two = da
if y==2: #如果为2第一个字母为小写
z=randint(0,25)
three=xiao
else:
z=randint(0,25)
three=da
numbers = randint(1000000,99999999)
g=str(one)+str(two)+str(three)+'.'+str(numbers)
print(g)
cc()
def cc():
three_engling()
dcdy()
tt()
dd()
sc()
cc()
@nizitao @python爱好者.
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