python 44课0题，我感觉源程序好像不对呢
# 测试高位是否有得“借”，那段好像有误呢？import time as t
class MyTimer:
def __init__(self):
self.unit = ['年', '月', '天', '小时', '分钟', '秒']
self.borrow =
self.prompt = "未开始计时！"
self.lasted = []
self.begin = 0
self.end = 0
def __str__(self):
return self.prompt
__repr__ = __str__
def __add__(self, other):
prompt = "总共运行了"
result = []
for index in range(6):
result.append(self.lasted + other.lasted)
if result:
prompt += (str(result) + self.unit)
return prompt
# 开始计时
def start(self):
self.begin = t.localtime()
self.prompt = "提示：请先调用 stop() 停止计时！"
print("计时开始...")
# 停止计时
def stop(self):
if not self.begin:
print("提示：请先调用 start() 进行计时！")
else:
self.end = t.localtime()
self._calc()
print("计时结束！")
# 内部方法，计算运行时间
def _calc(self):
self.lasted = []
self.prompt = "总共运行了"
for index in range(6):
temp = self.end - self.begin
# 低位不够减，需向高位借位
if temp < 0:
# 测试高位是否有得“借”，没得借的话向再高位借......
i = 1
while self.lasted < 1:
self.lasted += self.borrow - 1
self.lasted -= 1
i += 1 #当i 等于2时，对self.lasted<1,进行测试，如果self.lasted=0时条件成立，执行下面的语句self.lasted += self.borrow - 1
#我感觉不应该减1了，而是self.lasted += self.borrow，因为当i=1时index-1位，已经被借走一位，i=2轮循环时不需要再被借走了
self.lasted.append(self.borrow + temp)
self.lasted -= 1
else:
self.lasted.append(temp)
# 由于高位随时会被借位，所以打印要放在最后
for index in range(6):
if self.lasted:
self.prompt += str(self.lasted) + self.unit
# 为下一轮计时初始化变量
self.begin = 0
self.end = 0
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