代码小白liu 发表于 2022-4-13 16:29:08

问题求助

'''
请用已学过的知识编写程序,找出小甲鱼藏在下边这个长字符串中的密码,密码的埋藏点符合以下规律:Y5d|MAp
Y5d|MAp
    a) 每位密码为单个小写字母
    b) 每位密码的左右两边均有且只有三个大写字母
'''
password = ""
with open("string2.txt","r",encoding="utf-8") as f:
    content = f.read()
    length = len(content)
    for i in range(length):
      if content == "\n":
            continue
      if content.islower() and content.isupper() and len(content) == 3 \
                and content.isupper() and len(content) == 3:

            if content.islower() and content.islower():
      
                password +=content

    print(password)
content 如下
ACFlCTLIQlAIVMTqHFkswqbDDHtpgcWaXSSglUYKE
lqNsYCyaQXBzrFUbkAUAWAKrDgDtAlGMBqWQhpEwquZqWZJpslUfMllCwWptqINjrOBTLuPzwvXNbLCx
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qKWGc


和答案差了一点,不知道是哪里没考虑全

isdkz 发表于 2022-4-13 21:02:10

因为content中有换行,得先把换行去掉:
'''
请用已学过的知识编写程序,找出小甲鱼藏在下边这个长字符串中的密码,密码的埋藏点符合以下规律:Y5d|MAp
Y5d|MAp
    a) 每位密码为单个小写字母
    b) 每位密码的左右两边均有且只有三个大写字母
'''
password = ""
with open("string2.txt","r",encoding="utf-8") as f:
    content = f.read().replace('\n', '')                                       # 注意这里
    length = len(content)
    for i in range(length):
      if content == "\n":
            continue
      if content.islower() and content.isupper() and len(content) == 3 \
                and content.isupper() and len(content) == 3:

            if content.islower() and content.islower():
      
                password +=content

    print(password)

代码小白liu 发表于 2022-4-13 21:07:17

isdkz 发表于 2022-4-13 21:02
因为content中有换行,得先把换行去掉:

原本代码的12行不是将已经考虑了吗

isdkz 发表于 2022-4-13 21:12:44

代码小白liu 发表于 2022-4-13 21:07
原本代码的12行不是将已经考虑了吗

这样子考虑不太合理,因为换行影响的不是对当前字符的判断,

所以你有没有跳过没有区别,因为换行也不满足后面的 content.islower(),

但是它会影响对当前字符的前 3 个字符和后 3 个字符的判断,换行并不是字母,但是却可以忽略,

你不去掉换行的话,当前字符的前三个字符或后三个字符包括换行显然是不合理的
页: [1]
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