实验七答案
写了很长时间的代码，有兴趣可以看看assume cs:code,ds:data,es:table
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 34980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup('year summ ne ?? ')
table ends
code segment
start:mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov cx,21
mov bx,0
mov si,0
s0: mov ax,.0
mov es:,ax
add si,2
add bx,2
mov ax,.0
mov es:,ax
add si,14
add bx,2
loop s0
；将年份存入table段
mov cx,21
mov si,5
mov bx,0
s1: mov ax,.54h
mov es:,ax
add si,2
add bx,2
mov ax,.54h
mov es:,ax
add si,14
add bx,2
loop s1
；将收入存入table段
mov cx,21
mov si,0ah
mov bx,0
s2: mov ax,.0a8h
mov es:,ax
add si,10h
add bx,2
loop s2
；将员工数存入table段
mov cx,21
mov si,5
mov di,0dh
mov bx,0ah
s3: mov ax,es:
add si,2
mov dx,es:
div word ptr es:
mov es:,ax
add di,10h
add si,14
add bx,10h
loop s3
；从table段中读取收入和员工数，相除，将结果存入table
mov ax,4c00h
int 21h
code ends
end start
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