蛋套小哥哥 发表于 2012-8-31 20:39:08

求大家解析一下汇编代码


alloc(newmem,2048) //2kb should be enough
label(returnhere)
label(originalcode)
label(exit)
newmem: //this is allocated memory, you have read,write,execute access
originalcode:
mov ,00000004
mov eax,
pop esi
pop ecx
ret
exit:
jmp returnhere
00458465:
jmp newmem
returnhere:

dealloc(newmem)

好的有奖励!!!!
00458465:
mov eax,
pop esi
pop ecx
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