一个关于字典的小问题
]统计字符串"thebookisborrowedbyjack”中每个字母的出现次数，将结果保存到一个字典对象中，其中key为字母，value为字母出现的次数，对字典中的数据按照字母出现的次数(value值) 进行排序 s="sdluhflqsjidoiqwejfoljsdlkjkaslkdjfjklsdhkweqhfkqwhefksklafglsdfjkashjkldfhklasdhfjksahdfjkhqedhieuwf"t={}
for x in range(97,123):
t=0
for x in s:
t+=1
for x in t:
if t>0:
print(x,t) 还得按value 排序啊
s="sdluhflqsjidoiqwejfoljsdlkjkaslkdjfjklsdhkweqhfkqwhefksklafglsdfjkashjkldfhklasdhfjksahdfjkhqedhieuwf"
t={}
for x in range(97,123):
t=0
for x in s:
t+=1
res=sorted(t.items(),key=lambda kv:kv,reverse=True)
for x in res:
if x>0:
print(x)
('k', 13)
('f', 11)
('d', 10)
('h', 10)
('j', 10)
('l', 10)
('s', 10)
('a', 5)
('e', 5)
('q', 5)
('w', 4)
('i', 3)
('o', 2)
('u', 2)
('g', 1) 希望对你有帮助
#################################方法1用Counter函数
from collections import Counter
str_yuanma='thebookisborrowedbyjack'
count = Counter(str_yuanma)
print(count)
#################################方法2用字符串先转成列表，在用列表统计重复元素放入字典
str_yuanma='thebookisborrowedbyjack'
list=[]
for i in str_yuanma:
list.append(i)
dict = {}
for key in list:
dict = dict.get(key, 0) + 1
# print(list)
# print(dict)
print (dict) >>> string = "thebookisborrowedbyjack"
>>> lst = sorted({letter : string.count(letter) for letter in set(string)}.items(), key=lambda x : x)
>>> lst
[('d', 1), ('h', 1), ('s', 1), ('c', 1), ('y', 1), ('t', 1), ('i', 1), ('a', 1), ('w', 1), ('j', 1), ('e', 2), ('k', 2), ('r', 2), ('b', 3), ('o', 4)] s = 'thebookisborrowedbyjack'
res = {}
for i in s:
res = s.count(i)
res = sorted(res.items(), key=lambda v: v)
print(res)
页:
[1]