装饰器流程判断
现有代码如下@fun_d(minNum=10,maxNum=20)
def fun1(a,b):
return a+b
@fun_d(minNum=10,maxNum=20)
def fun2(a,b,c):
return a+b-c
要求实现 fun_d 装饰器,要求:
确保使用该装饰器的方法参数都是int类型,否则抛出异常
(提示可以使用 isinstance(i,int) 判断i是否是int 类型)
参数的值在minNum 和 maxNum之间
如果参数值不符合,抛出异常 def fun_d(minNum, maxNum):
def outer(func):
nonlocal minNum, maxNum
def inner(*args):
nonlocal minNum, maxNum, func
for i in args:
assert isinstance(i, int)
assert minNum <= i <= maxNum
return func(*args)
return inner
return outer
@fun_d(minNum=10,maxNum=20)
def fun1(a,b):
return a+b
fun1(10, 20)
30
fun1(1, 2)
Traceback (most recent call last):
File "<pyshell#33>", line 1, in <module>
fun1(1, 2)
File "<pyshell#29>", line 8, in inner
assert minNum <= i <= maxNum
AssertionError
fun1('1', '2')
Traceback (most recent call last):
File "<pyshell#34>", line 1, in <module>
fun1('1', '2')
File "<pyshell#29>", line 7, in inner
assert isinstance(i, int)
AssertionError
@fun_d(minNum=10,maxNum=20)
def fun2(a,b,c):
return a+b-c
fun2(1, 2, 3)
Traceback (most recent call last):
File "<pyshell#37>", line 1, in <module>
fun2(1, 2, 3)
File "<pyshell#29>", line 8, in inner
assert minNum <= i <= maxNum
AssertionError
fun2('1', '2', '3')
Traceback (most recent call last):
File "<pyshell#38>", line 1, in <module>
fun2('1', '2', '3')
File "<pyshell#29>", line 7, in inner
assert isinstance(i, int)
AssertionError
fun2(10, 15, 20)
5
def fun_d(minNum, maxNum):
def outer(func):
nonlocal minNum, maxNum
def inner(*args):
nonlocal minNum, maxNum, func
for i in args:
assert isinstance(i, int)
assert minNum <= i <= maxNum
return func(*args)
return inner
return outer
@fun_d(minNum=10,maxNum=20)
def fun1(a,b):
return a+b
@fun_d(minNum=10,maxNum=20)
def fun2(a,b,c):
return a+b-c
f = fun1(10,20),fun2(10,20,15) def fun_d(minNum = 10 , maxNum = 20):
def outer(func):
def inner(* args):
for x in args :
if not type(x) == int or x < minNum or x > maxNum :
return str(args) + ' : parameter type or value error.'
else :
return func(* args)
return inner
return outer
@fun_d(10 , 20)
def fun1(a,b):
return a+b
@fun_d(10 , 20)
def fun2(a,b,c):
return a+b-c
print(fun1(15 , 16)) # 合格
print(fun1(3 , 15)) # 不合格
print(fun2(12 , 13 , 15)) # 合格
print(fun2(2 , 3 , 5)) # 不合格
print(fun1('abc' , 123)) # 不合格
print(fun2('abc' , 'bcd' , 123)) # 不合格 jackz007 发表于 2022-11-22 11:57
看起来确实更简洁一些,手动最佳~{:10_256:}
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