关于递归的问题,请大佬进来看看
#include <stdio.h>struct cityLN {
char name;
int population;
struct cityLN *next;
};
void printCities(struct cityLN *ct);
struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt);
int main(){
struct cityLN c1 = {"Hiratsuka", 258, NULL},
c2 = {"Odawara", 190, NULL},
c3 = {"Yokosuka", 396, NULL},
c4 = {"Kamakura", 172, NULL},
c5 = {"Chigasaki", 242, NULL},
c6 = {"Fujisawa", 434, NULL};
struct cityLN *head = NULL;
head = &c1; c1.next = &c2;c2.next = &c3; c3.next = &c4; c4.next = &c5; c5.next = &c6;
printf("Original: \n");
printCities(head);
printf("reverse: \n");
head = reverseCitiesRecursive(head, NULL);
printCities(head);
return 0;
}
void printCities(struct cityLN *ct){
if (ct != NULL) {
printf("(%-10s: population = %3d)", ct->name, ct->population);
printf("%s", (ct->next != NULL) ? " ->\n" : "");
printCities(ct->next);
}
else
putchar('\n');
}
struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt){
}
最后一行的reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt)函数设计,他原来的顺序是c1->c2->c3->c4->c5->c6这样依次打印出来,而这个函数的作用是让他变成c6->c5->c4->c3->c2->c1
但是问题就出在于必须使用递归,他的输入值时head,head是c1,如果把c1->next更改为NULL,那么这个递归就无法继续下去。卡在这里想了好久都不知道怎么解。我也思考了很多比如先倒过来但是不知道怎么下手,下面的图片是完成后运行代码的输出内容,请问下这个函数应该如何设计。
本帖最后由 jhq999 于 2022-12-6 19:37 编辑
#include <stdio.h>
struct cityLN {
char name;
int population;
struct cityLN *next;
};
void printCities(struct cityLN *ct);
struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt);
int main(){
struct cityLN c1 = {"Hiratsuka", 258, NULL},
c2 = {"Odawara", 190, NULL},
c3 = {"Yokosuka", 396, NULL},
c4 = {"Kamakura", 172, NULL},
c5 = {"Chigasaki", 242, NULL},
c6 = {"Fujisawa", 434, NULL};
struct cityLN *head = NULL;
head = &c1; c1.next = &c2;c2.next = &c3; c3.next = &c4; c4.next = &c5; c5.next = &c6;
printf("Original: \n");
printCities(head);
printf("reverse: \n");
struct cityLN * tmp=head;
head = reverseCitiesRecursive(head, head->next);
tmp->next=NULL;
printCities(head);
return 0;
}
void printCities(struct cityLN *ct){
if (ct != NULL) {
printf("(%-10s: population = %3d)", ct->name, ct->population);
printf("%s", (ct->next != NULL) ? " ->\n" : "");
printCities(ct->next);
}
else
putchar('\n');
}
struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt){
if (dt->next == NULL) {
dt->next=ct;
return dt;
}
struct cityLN * tmp=dt->next;
dt->next=ct;
return reverseCitiesRecursive(dt,tmp);
}
struct cityLN * reverseCitiesRecursive(struct cityLN *head){
struct cityLN *p=head->next,*tmp;
head->next=NULL;
while(p->next)
{
tmp=p->next;
p->next=head;
head=p;
p=tmp;
}
p->next=head;
return p;
} 本帖最后由 Sagiri 于 2022-12-6 20:25 编辑
函数形式一定要这样吗? struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt);
-----------
取巧了{:10_297:}
struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt = nullptr){
if (ct->next == nullptr) return ct;
cityLN *lastCity = reverseCitiesRecursive(ct->next);
ct->next->next = ct;
ct->next = nullptr;
return lastCity;
} jhq999 发表于 2022-12-6 19:27
struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt){
if (dt->next == NULL) {
dt->next=ct;
return dt;
}
struct cityLN * tmp=dt->next;
dt->next=ct;
return reverseCitiesRecursive(dt,tmp);
}
大佬这个函数存在问题,第一个的时候dt是NULL,就执行不下去了- - Sagiri 发表于 2022-12-6 20:18
函数形式一定要这样吗? struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt); ...
大佬,不能更改- -就好像考试总不能吧题目改了吧,我到现在还是不知道怎么做 壳970527 发表于 2022-12-8 09:47
大佬这个函数存在问题,第一个的时候dt是NULL,就执行不下去了- -
//当时考虑不周
struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt){
if (dt == NULL) {
return ct;
}
struct cityLN * tmp=dt->next;
dt->next=ct;
return reverseCitiesRecursive(dt,tmp);
}
jhq999 发表于 2022-12-8 10:23
感谢大佬,真的我想了好久,感觉怎么想都是有点祖父悖论的感觉 本帖最后由 jhq999 于 2022-12-8 10:53 编辑
壳970527 发表于 2022-12-8 10:30
感谢大佬,真的我想了好久,感觉怎么想都是有点祖父悖论的感觉
我把三楼的改了改,应该是你要的
#include <stdio.h>
struct cityLN {
char name;
int population;
struct cityLN *next;
};
void printCities(struct cityLN *ct);
struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt);
int main(){
struct cityLN c1 = {"Hiratsuka", 258, NULL},
c2 = {"Odawara", 190, NULL},
c3 = {"Yokosuka", 396, NULL},
c4 = {"Kamakura", 172, NULL},
c5 = {"Chigasaki", 242, NULL},
c6 = {"Fujisawa", 434, NULL};
struct cityLN *head = NULL;
head = &c1; c1.next = &c2;c2.next = &c3; c3.next = &c4; c4.next = &c5; c5.next = &c6;
printf("Original: \n");
printCities(head);
printf("reverse: \n");
head = reverseCitiesRecursive(head, NULL);
printCities(head);
return 0;
}
void printCities(struct cityLN *ct){
if (ct != NULL) {
printf("(%-10s: population = %3d)", ct->name, ct->population);
printf("%s", (ct->next != NULL) ? " ->\n" : "");
printCities(ct->next);
}
else
putchar('\n');
}
struct cityLN * reverseCitiesRecursive(struct cityLN *ct, struct cityLN *dt ){
if (ct== NULL) return dt;
struct cityLN *lastCity = reverseCitiesRecursive(ct->next,ct);
ct->next=dt;
return lastCity;
}
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