这个代码到底哪里出了问题啊
一members = {
"鱼C工作室" : {"小甲鱼":83, "不二如是":89, "二师兄":64, "小师妹":75, "鱼小二":96},
"复仇者联盟" : {"钢铁侠":85, "绿巨人":39, "黑寡妇":82, "鹰眼":73, "雷神":99},
"奥特曼家族" : {"迪迦":99, "艾斯":84, "泰罗":63, "佐菲":78, "赛文":78}}
x = []
for k,v in members.items():
x.append(str(k+":"+min(v,key=v.get)))
print(x)
二
members = {
"鱼C工作室" : {"小甲鱼":83, "不二如是":89, "二师兄":64, "小师妹":75, "鱼小二":96},
"复仇者联盟" : {"钢铁侠":85, "绿巨人":39, "黑寡妇":82, "鹰眼":73, "雷神":99},
"奥特曼家族" : {"迪迦":99, "艾斯":84, "泰罗":63, "佐菲":78, "赛文":78}}
x = [':'.join((i, min(members.items(), key = lambda x:x))) for i in members]
print(x)
三
members = {
"鱼C工作室" : {"小甲鱼":83, "不二如是":89, "二师兄":64, "小师妹":75, "鱼小二":96},
"复仇者联盟" : {"钢铁侠":85, "绿巨人":39, "黑寡妇":82, "鹰眼":73, "雷神":99},
"奥特曼家族" : {"迪迦":99, "艾斯":84, "泰罗":63, "佐菲":78, "赛文":78}}
x = [':'.join(k,min(v,key=v.get) for k,v in members.items())]
print(x)
为什么一、二可以运行，三就报错呢 本帖最后由 isdkz 于 2023-1-7 11:21 编辑
一：在生成器表达式里面 k,min(v,key=v.get) 需要加一个括号表示元组
二：因为生成器表达式的生成元素都是元组，所以不能直接用 join
members = {
"鱼C工作室" : {"小甲鱼":83, "不二如是":89, "二师兄":64, "小师妹":75, "鱼小二":96},
"复仇者联盟" : {"钢铁侠":85, "绿巨人":39, "黑寡妇":82, "鹰眼":73, "雷神":99},
"奥特曼家族" : {"迪迦":99, "艾斯":84, "泰罗":63, "佐菲":78, "赛文":78}}
x = [':'.join(i) for i in ((k,min(v,key=v.get)) for k,v in members.items())]
print(x) 谢谢答复！我想再问一下 key=v.get 是什么意思，什么用法 key是取最小值的依据，但是v.get是什么用法
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