爬虫
import requestsfrom lxml import html
etree = html.etree
url = 'http://fund.eastmoney.com/data/rankhandler.aspx'
header = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/108.0.0.0 Safari/5.36"
}
parms = {
"op": "ph",
"dt": "kf",
"ft": "zq",
"rs":"",
"gs": "0",
"sc": "1nzf",
"st": "desc",
"sd": "2022-01-17",
"ed": "2023-01-17",
"qdii": "041|",
"tabSubtype": "041,,,,,",
"pi": "1",
"pn": "50",
"dx": "1",
"v": "0.5745516544026257"
}
response = requests.get(url=url,headers=header,params=parms)
page = response.text
print(page)
大佬们。为什么这个一爬取就显示var rankData ={ErrCode:-999,Data:"无访问权限"}
本帖最后由 tommyyu 于 2023-1-17 11:17 编辑
这个的页面是不是就只有“var rankData ={ErrCode:-999,Data:"无访问权限"}”,为啥我点开看也是这样{:10_282:} 你这个链接不是还带了别的参数吗?在请求的时候 url 带上完整的参数,直接在那里右键复制url
isdkz 发表于 2023-1-17 11:14
你这个链接不是还带了别的参数吗?在请求的时候 url 带上完整的参数,直接在那里右键复制url
参数都带了,还是显示var rankData ={ErrCode:-999,Data:"无访问权限"} tommyyu 发表于 2023-1-17 11:14
这个的页面是不是就只有“var rankData ={ErrCode:-999,Data:"无访问权限"}”,为啥我访问也是这样{:10_282 ...
我也不知道{:5_100:} 哈岁NB 发表于 2023-1-17 11:17
参数都带了,还是显示var rankData ={ErrCode:-999,Data:"无访问权限"}
你这个请求是打开哪个链接出来的,我帮你调试看看 加上 Referer,这个字段是说明你是从哪个链接发起请求的,这是一种防盗链的手段,只允许你从特定的链接发起请求
import requests
from lxml import html
etree = html.etree
url = 'http://fund.eastmoney.com/data/rankhandler.aspx'
header = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/108.0.0.0 Safari/5.36",
'Referer':'http://fund.eastmoney.com/data/fundranking.html' # 加上这个
}
parms = {
"op": "ph",
"dt": "kf",
"ft": "zq",
"rs":"",
"gs": "0",
"sc": "1nzf",
"st": "desc",
"sd": "2022-01-17",
"ed": "2023-01-17",
"qdii": "041|",
"tabSubtype": "041,,,,,",
"pi": "1",
"pn": "50",
"dx": "1",
"v": "0.5745516544026257"
}
response = requests.get(url=url,headers=header,params=parms)
page = response.text
print(page) import requests
from lxml import html
etree = html.etree
url = 'http://fund.eastmoney.com/data/rankhandler.aspx'
header = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/108.0.0.0 Safari/5.36",
'Referer':'http://fund.eastmoney.com/data/fundranking.html' # 加上这个,说明你是从哪个链接发起请求的,有一些url只允许从特定的链接发起请求
}
parms = {
"op": "ph",
"dt": "kf",
"ft": "zq",
"rs":"",
"gs": "0",
"sc": "1nzf",
"st": "desc",
"sd": "2022-01-17",
"ed": "2023-01-17",
"qdii": "041|",
"tabSubtype": "041,,,,,",
"pi": "1",
"pn": "50",
"dx": "1",
"v": "0.5745516544026257"
}
response = requests.get(url=url,headers=header,params=parms)
page = response.text
print(page) isdkz 发表于 2023-1-17 11:34
好的好的,成功了
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