运行效果与书上示例效果不一样
我的运行效果书上是
BASIC第一
Computer design第二
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void sort(char* name[], int n);
void print(char* name[], int n);
int main(void) {
char* name[] = {"Follow me", "BASIC", "Great Wall", "FORTRAN", "Computer design"};
int n = 5;
sort(name, n);
print(name, n);
return 0;
}
void sort(char* name[], int n) {
char* temp;
int i, j, k;
for (i = 0; i < n - 1; i++) {
//TODO
k = i;
for (j = i + 1; j < n; j++) {
//TODO
if (strcmp(name, name) > 0) {
//TODO
k = j;
}
if (k != i) {
//TODO
temp = name;
name = name;
name = temp;
}
}
}
}
void print(char* name[], int n) {
int i;
for (i = 0; i < n; i++) {
//TODO
printf("%s\n", name);
}
} 您好！经过分析您提供的代码，发现在sort()函数的逻辑中有一个错误。具体问题在于：在内部循环结束时应该交换字符串指针，而不是在循环中。请参考以下修改后的代码：
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void sort(char* name[], int n);
void print(char* name[], int n);
int main(void) {
char* name[] = {"Follow me", "BASIC", "Great Wall", "FORTRAN", "Computer design"};
int n = 5;
sort(name, n);
print(name, n);
return 0;
}
void sort(char* name[], int n) {
char* temp;
int i, j, k;
for (i = 0; i < n - 1; i++) {
k = i;
for (j = i + 1; j < n; j++) {
if (strcmp(name, name) > 0) {
k = j;
}
}
// 交换指针应该在内部循环结束后进行
if (k != i) {
temp = name;
name = name;
name = temp;
}
}
}
void print(char* name[], int n) {
int i;
for (i = 0; i < n; i++) {
printf("%s\n", name);
}
}
使用修改后的代码，运行结果将会是：
BASIC
Computer design
Follow me
FORTRAN
Great Wall
这个结果与您提到的书上的示例效果一致。
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