请大师帮做个键是6位数的字典，谢谢
请大师帮做个字典，谢谢1:000395/菲利华/9.38%/536.81/29,524.39。；2:00593/新雷能/8.82%/653.62/27,765.83。；10:603105/芯能科技/2.51%/535.72/7,891.21。；2:1593/新雷/8.82%/653.62/27,765.83。
怎么把上面做成如下字典：键是冒号和斜杠之间的6位数，值是第二个斜杠后的值
{‘000395’:9.38,‘603105’:2.51} 可以通过正则表达式和Python字典解析的方式实现，代码如下：
import re
text = "1:000395/菲利华/9.38%/536.81/29,524.39。；2:00593/新雷能/8.82%/653.62/27,765.83。；10:603105/芯能科技/2.51%/535.72/7,891.21。；2:1593/新雷/8.82%/653.62/27,765.83。"
pattern = re.compile(r'(\d{6})/[^/]*/(\d+\.\d+)%')
result = {m.group(1): float(m.group(2)) for m in pattern.finditer(text)}
print(result)
运行上面的代码，将得到所需的字典结果：
{'000395': 9.38, '603105': 2.51}
普通思路仍然可行：
s="1:300395/菲利华/9.38%/536.81/29,524.39。；2:300593/新雷能/8.82%/653.62/27,765.83。；10:60305/芯能科技/2.51%/535.72/7,891.21"
dic={}
for x in s.split("；"):
m=x.split("/")
if len(m.split(":"))==6:
dic.split(":")]=m[:-1]
print(dic)
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