【朱迪的LeetCode刷题笔记】1480. Running Sum of 1d Array #Easy #Python
本帖最后由 Judie 于 2023-5-23 02:22 编辑Given an array nums. We define a running sum of an array as runningSum = sum(nums…nums).
Return the running sum of nums.
Example 1:
Input: nums =
Output:
Explanation: Running sum is obtained as follows: .
Example 2:
Input: nums =
Output:
Explanation: Running sum is obtained as follows: .
Example 3:
Input: nums =
Output:
Constraints:
1 <= nums.length <= 1000
-10^6 <= nums <= 10^6
class Solution(object):
def runningSum(self, nums):
"""
:type nums: List
:rtype: List
"""
Judy
class Solution(object):
def runningSum(self, nums):
"""
:type nums: List
:rtype: List
"""
i = 1
l = len(nums)
s = nums
runningSum =
while i < l:
s += nums
runningSum.append(s)
i +=1
return runningSum
Gray
class Solution(object):
def runningSum(self, nums):
"""
:type nums: List
:rtype: List
"""
ans = []
temp = 0
for x in nums:
ans.append(temp + x)
temp = temp + x
return ans
不错，希望更下去 不二如是 发表于 2023-5-23 06:35
不错，希望更下去
谢谢 我努力！
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