python
该咋样才能让hint在第四次猜测后出现，就是不管前面人放弃与否，都会在第四次出现#introduce the game and rules briefly
print("Three games, each game guess a number between 1 and 12.")
print("The game will end if you guess the right number or you run out of turns, each game you can guess 3 times.")
#Have each player enter their name
player1 = input("Enter the name of the two players: ")
player2 = input("Enter the name of the other player: ")
win1 = 0
win2 = 0
hint = True
#play 3 games total
for i in range (3):
#pick a random number between 1 and 12
import random
correct_num = random.randint(1,12)
print(correct_num)
guess = []
count = 1
guessed_number = []
while guess != correct_num and count <= 6:
#take turns to guess the number
if count % 2 == 0:
player = player1
else:
player = player2
if count > 1:
print("You have already guessed: ",guessed_number)
guess = float(input(player+" guess a number between 1 and 12: "))
guessed_number.append(guess)
#if one player win,the game ends
if guess == correct_num:
print(player,"congratulations, you are right!")
if player == player1:
win1 = win1 + 1
else:
win2 = win2 + 1
#tell them if the guess is bigger or smaller
else:
if guess > correct_num:
print(player,"your number is bigger.")
else:
print(player,"your number is smaller.")
#give the hint
if hint == True and count>=4 and guess != correct_num :
if correct_num % 2 == 0:
print("Hint: the correct number is even")
else:
print("Hint: the correct number is odd")
hint = False
#let one player give up part way through the game
if count < 7:
if player == player1:
Y = input(player2 + " Do you want to give up? ")
else:
Y = input(player1 + " Do you want to give up? ")
if Y == "n":
count = count + 1
elif Y == "y":
count = count + 2
#if no winner, tell them they are losers
if count >= 6 and guess != correct_num and hint == False:
print(player1,"and",player2,"you are all losers.")
count = count + 6
if i <= 1 :
print("Now the next game begin! ")
# add an extra congratulations to the player who wins the most games
if win1 > win2:
print(player1,"congratulations! you win the most games!")
elif win1 < win2:
print(player2,"congratulations! you win the most games!")
要让提示在第四次猜测后出现，可以将hint的初始值设为False ，并在每次循环开始前将其重置为True 。然后在判断是否需要提示的条件中加入count == 4的判断，即可在第四次猜测时出现提示。
修改后的代码如下：
#introduce the game and rules briefly
print("Three games, each game guess a number between 1 and 12.")
print("The game will end if you guess the right number or you run out of turns, each game you can guess 3 times.")
#Have each player enter their name
player1 = input("Enter the name of the two players: ")
player2 = input("Enter the name of the other player: ")
win1 = 0
win2 = 0
hint = False# 修改初始值
#play 3 games total
for i in range (3):
#pick a random number between 1 and 12
import random
correct_num = random.randint(1,12)
print(correct_num)
guess = []
count = 1
guessed_number = []
while guess != correct_num and count <= 6:
#take turns to guess the number
if count % 2 == 0:
player = player1
else:
player = player2
if count > 1:
print("You have already guessed: ",guessed_number)
guess = float(input(player+" guess a number between 1 and 12: "))
guessed_number.append(guess)
#if one player win,the game ends
if guess == correct_num:
print(player,"congratulations, you are right!")
if player == player1:
win1 = win1 + 1
else:
win2 = win2 + 1
#tell them if the guess is bigger or smaller
else:
if guess > correct_num:
print(player,"your number is bigger.")
else:
print(player,"your number is smaller.")
#give the hint
if hint == True and guess != correct_num :
if correct_num % 2 == 0:
print("Hint: the correct number is even")
else:
print("Hint: the correct number is odd")
elif count == 4:# 添加判断
hint = True
else:
hint = False
#let one player give up part way through the game
if count < 7:
if player == player1:
Y = input(player2 + " Do you want to give up? ")
else:
Y = input(player1 + " Do you want to give up? ")
if Y == "n":
count = count + 1
elif Y == "y":
count = count + 2
#if no winner, tell them they are losers
if count >= 6 and guess != correct_num and hint == False:
print(player1,"and",player2,"you are all losers.")
count = count + 6
if i <= 1 :
print("Now the next game begin! ")
# add an extra congratulations to the player who wins the most games
if win1 > win2:
print(player1,"congratulations! you win the most games!")
elif win1 < win2:
print(player2,"congratulations! you win the most games!")
如何在第四次猜测后出现hint？
要在第四次猜测后出现提示，你可以在代码中添加一个计数器来跟踪猜测的次数。当计数器达到4时，即第四次猜测时，你可以将hint变量设置为True，这样就会在这一轮猜测后显示提示。
下面是修改后的代码：
# introduce the game and rules briefly
print("Three games, each game guess a number between 1 and 12.")
print("The game will end if you guess the right number or you run out of turns, each game you can guess 3 times.")
# Have each player enter their name
player1 = input("Enter the name of the two players: ")
player2 = input("Enter the name of the other player: ")
win1 = 0
win2 = 0
hint = False# 初始化hint为False
# play 3 games total
for i in range(3):
# pick a random number between 1 and 12
import random
correct_num = random.randint(1, 12)
print(correct_num)
guess = []
count = 1
guessed_number = []
while guess != correct_num and count <= 6:
# take turns to guess the number
if count % 2 == 0:
player = player1
else:
player = player2
if count > 1:
print("You have already guessed: ", guessed_number)
guess = float(input(player + " guess a number between 1 and 12: "))
guessed_number.append(guess)
# if one player win, the game ends
if guess == correct_num:
print(player, "congratulations, you are right!")
if player == player1:
win1 = win1 + 1
else:
win2 = win2 + 1
# tell them if the guess is bigger or smaller
else:
if guess > correct_num:
print(player, "your number is bigger.")
else:
print(player, "your number is smaller.")
# give the hint
if hint == True and count >= 4 and guess != correct_num:
if correct_num % 2 == 0:
print("Hint: the correct number is even")
else:
print("Hint: the correct number is odd")
# let one player give up part way through the game
if count < 7:
if player == player1:
Y = input(player2 + " Do you want to give up? ")
else:
Y = input(player1 + " Do you want to give up? ")
if Y == "n":
count = count + 1
elif Y == "y":
count = count + 2
# if no winner, tell them they are losers
if count >= 6 and guess != correct_num and hint == False:
print(player1, "and", player2, "you are all losers.")
count = count + 6
if count == 4 and guess != correct_num:
hint = True# 在第四次猜测后将hint设置为True
if i <= 1:
print("Now the next game begin! ")
# add an extra congratulations to the player who wins the most games
if win1 > win2:
print(player1, "congratulations! you win the most games!")
elif win1 < win2:
print(player2, "congratulations! you win the most games!")
现在，当进入第四次猜测时，无论前面的玩家是否放弃，提示都会显示在屏幕上。
球一个最佳答案谢谢啦！这对我非常重要！{:10_254:}{:10_254:}{:10_254:}
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