求助一下
6-1 计算两个复数之积分数 10
作者 张泳
单位 浙大城市学院
本题要求实现一个计算复数之积的简单函数。
函数接口定义：
struct complex multiply(struct complex x, struct complex y);
其中struct complex是复数结构体，其定义如下：
struct complex{
int real;
int imag;
};
裁判测试程序样例：
#include <stdio.h>
struct complex{
int real;
int imag;
};
struct complex multiply(struct complex x, struct complex y);
int main()
{
struct complex product, x, y;
scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
product = multiply(x, y);
printf("(%d+%di) * (%d+%di) = %d + %di\n",
x.real, x.imag, y.real, y.imag, product.real, product.imag);
return 0;
}
/* 你的代码将被嵌在这里 */
输入样例：
3 4 5 6
输出样例：
(3+4i) * (5+6i) = -9 + 38i
这个函数怎么写 #include <stdio.h>
struct complex{
int real;
int imag;
};
struct complex multiply(struct complex x, struct complex y);
int main()
{
struct complex product, x, y;
scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
product = multiply(x, y);
printf("(%d+%di) * (%d+%di) = %d + %di\n",
x.real, x.imag, y.real, y.imag, product.real, product.imag);
return 0;
}
struct complex multiply(struct complex x, struct complex y) {
struct complex result;
result.real = x.real * y.real - x.imag * y.imag;
result.imag = x.real * y.imag + x.imag * y.real;
return result;
}
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