python中让一个玩家猜对字母之后一直猜，猜错后才换另一个人猜
这是我写完成的代码，请问怎么做到让一个玩家赢了之后可以一直让他猜？等他猜错之后就换另一个人猜？import random
def main():
f=open("cattle.txt")
text=f.readlines()
secretWord=random.choice(text)
secretWord=secretWord.strip('\n')
count=1
wrongCount=0
wrongList=[]
player1=input("Enter your name: ")
player2=input("Enter your name: ")
instructions(player1,player2)
blanks=initializeBlanks(secretWord)
while "#" in blanks and wrongCount < 5:
if count%2==0:
player=player1
else:
player=player2
count+=1
letter=getGuess(wrongList,player)
if letter in secretWord:
blanks=fillInBlanks(secretWord,blanks,letter,player)
else:
wrongList.append(letter)
wrongCount=wrongCount+1
print("Wrong guess!")
statusReport(wrongList,wrongCount,blanks)
display(wrongCount)
if not "#" in blanks:
print(player,"Congratulations! You are the winner!")
else:
print("You are both losers.")
def instructions(p1,p2):
print(p1,p2,"I will select a secret word and give you the number of the word.")
print("You need to guess the letters in the word.")
print("Correctly guessed letters will be uesd to fill in the blank, incorrecly guessed letters will be used to build a snowman.")
print("The game will end if you successfully guess all the secret letters or you have 5 wrong guesses.")
def getGuess(wrongList,player):
letter = input(player+"Guess a letter: ")
punct="~!@#$%^&*()_+?:<>"
if letter in wrongList:
print("You have guessed this letter.")
return getGuess(wrongList,player)
ifletter in punct:
print("This guess is invaild,guess again!")
return getGuess(wrongList,player)
else:
letter=letter.lower()
return letter
def statusReport(wrongList,wrongCount,blanks):
print("Current status: ")
print("You have guessed",wrongCount,"times wrong.")
print("The letters you have guessed wrong are",wrongList)
print("The secret word now is",blanks)
def initializeBlanks(s):
blanks=["#"]*len(s)
return blanks
def fillInBlanks(secretWord,blanks,l,player):
location=secretWord.index(l)
blanks=l
print(blanks)
if not "#" in blanks:
print(player,"Congratulations! You are the winner!")
return blanks
def display(wrongCount):
grid=[[' ',' ',' '],
[' ',' ',' '],
[' ',' ',' '],
['~','~','~']]
Dict={1:,
2:,
3:,
4:,
5:}
for key in (Dict.keys()):
if key<=wrongCount:
value=Dict
row=value
col=value
item=value
grid=item
for row in grid:
for col in row:
print(col,end=" ")
print("\n")
main()
你可以使用一个循环来实现让一个玩家赢了之后一直猜，等他猜错之后就换另一个玩家猜的功能。首先，在主函数中新增一个变量来记录当前猜字母的玩家，初始值为player1。然后在while循环中，打印出当前轮到哪个玩家猜，并接收玩家的猜测。如果猜测正确，则继续让当前玩家猜；如果猜测错误，则切换到另一个玩家猜。具体代码如下所示：
import random
def main():
f = open("cattle.txt")
text = f.readlines()
secretWord = random.choice(text)
secretWord = secretWord.strip('\n')
count = 1
wrongCount = 0
wrongList = []
player1 = input("Enter your name: ")
player2 = input("Enter your name: ")
currentPlayer = player1 # 当前猜字母的玩家
instructions(player1,player2)
blanks = initializeBlanks(secretWord)
while "#" in blanks and wrongCount < 5:
print(currentPlayer, "It's your turn to guess.")
letter = getGuess(wrongList, currentPlayer)
if letter in secretWord:
blanks = fillInBlanks(secretWord, blanks, letter, currentPlayer)
else:
wrongList.append(letter)
wrongCount = wrongCount + 1
print("Wrong guess!")
statusReport(wrongList, wrongCount, blanks)
display(wrongCount)
if not "#" in blanks:
print(currentPlayer, "Congratulations! You are the winner!")
# 当前玩家赢了之后，继续让他猜
continue
else:
# 猜错了，切换到另一个玩家
if currentPlayer == player1:
currentPlayer = player2
else:
currentPlayer = player1
print("You are both losers.")
# 其他函数的代码保持不变
在这个修改后的代码中，我们新增了一个currentPlayer变量来记录当前猜字母的玩家。然后在while循环中，先打印出当前轮到哪个玩家猜，再接收该玩家的猜测。如果猜测正确，则继续让当前玩家猜；如果猜测错误，则切换到另一个玩家猜。当一个玩家赢了之后，通过`continue`语句继续下一轮循环，即继续让他猜。直到有一个玩家猜错或者猜对所有字母，循环才会结束。
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