解决问题
请问这一题怎么解决？（用c语言）9.2. Exercise
Calling time (NULL) gives you a large integer. Use this value to calculate today's year, date, hours, and minutes.
Simplifying assumption:we pretend that each year has exactly365 days. The 15th of March is therefore day 83 in year 2011. (use that date to figure out today's "day number")(hint: how many seconds are there in a day?)
You cannot use struct for this assignment.
You cannot use any time-based functions from the standard library such asasctime or strftime.
You must use one function to calculate the year and day(pass inthe total seconds, and a reference to the year and day).
You must use a separate function to calculate the hours andminutes.(again, pass the total seconds, and a reference to the hours and minutes)
You must use a separate function to print the time; this functioncan only take as arguments the year, day, hour, and minutes.
handle leap-years correctly, and print the month as well. 这道题目要求你使用C语言来计算今天的年份、日期、小时和分钟。
首先，我们可以使用`time(NULL)`函数获取当前时间对应的秒数。然后，我们假设每年有365天，并且基于给出的日期（3月15日，2011年）来计算今天是一年中的第几天。提示里提到了一天有多少秒，这个信息可以帮助我们计算。
根据上述条件，可以编写如下代码：
#include <stdio.h>
#include <time.h>
// 计算年份和日期
void calculateYearAndDay(time_t seconds, int *year, int *day) {
// 计算今天是一年中的第几天
*day = seconds / (24 * 60 * 60) + 83;
// 计算年份
*year = 2011 + (*day / 365);
}
// 计算小时和分钟
void calculateHourAndMinute(time_t seconds, int *hour, int *minute) {
// 计算小时和分钟
*hour = (seconds % (24 * 60 * 60)) / 3600;
*minute = (seconds % 3600) / 60;
}
// 打印时间
void printTime(int year, int day, int hour, int minute){
printf("Today is: %d-%d, Time: %02d:%02d", year, day, hour, minute);
}
int main() {
time_t currentTime = time(NULL);
int year, day, hour, minute;
calculateYearAndDay(currentTime, &year, &day);
calculateHourAndMinute(currentTime, &hour, &minute);
printTime(year, day, hour, minute);
return 0;
}
这段代码首先使用`time(NULL)`函数获取当前时间对应的秒数。然后，调用`calculateYearAndDay`函数计算年份和日期，传入秒数和指向年份和日期变量的指针。接着，调用`calculateHourAndMinute`函数计算小时和分钟，同样传入秒数和指向小时和分钟变量的指针。最后，调用`printTime`函数将计算出的时间打印出来。
注意，这段代码没有考虑闰年的情况。如果你希望正确处理闰年，你需要在`calculateYearAndDay`函数中添加相应的逻辑。
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