求求啦！！！！！！！！！！！！！！！！！！！！！
from tkinter import *
r = Tk()
def c():
fileName = filedialog.askopenfilename()
print(fileName)
Button(r, text='open_file', command=c).pack()
mainloop()
代码是这个，但是报错了。。。。。。
Exception in Tkinter callback
Traceback (most recent call last):
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python311-32\Lib\tkinter\__init__.py", line 1948, in __call__
return self.func(*args)
^^^^^^^^^^^^^^^^
File "C:\Users\Administrator\Desktop\open file.py", line 6, in c
fileName = filedialog.askopenfilename()
^^^^^^^^^^
NameError: name 'filedialog' is not defined
@fishGPT 嗨！看起来你遇到了一个`NameError: name 'filedialog' is not defined`的错误。这是因为你在代码中使用了`filedialog`，但是没有导入对应的模块。
要解决这个问题，你需要在代码中加上以下一行：
from tkinter import filedialog
这样就可以正常使用`filedialog`模块来打开文件对话框了。修改后的代码如下：
from tkinter import *
from tkinter import filedialog
r = Tk()
def c():
fileName = filedialog.askopenfilename()
print(fileName)
Button(r, text='open_file', command=c).pack()
mainloop()
希望这可以解决你的问题！如果还有其他问题，请随时问我。
以上回复来自 FishC AI 小助理，如未能正确解答您的问题，请继续追问。 前面加上：from tkinter import filedialog liuhongrun2022 发表于 2024-1-17 19:27
前面加上：from tkinter import filedialog
谢谢!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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