汇编语言程序设计问题
功能是读指定文件内容显示在屏幕上，不知道为什么，只读一个字节就报错了谁帮我看看？？data segment
string db "file open is wrong$"
string1 db "reading is error$"
filename db '1.txt',0
buffer db ?
data ends
code segment
assume cs:code,ds:data
start:
mov ax,data
mov ds,ax
clc
mov dx,offset filename
mov ax,3d00h
int 21h
jnc open_ok
mov dx,offset string
call tishi
jmp over
open_ok proc
mov bx,ax
push ax
push bx
return0:call du
jc du_error
cmp al,1ah
je close
call xianshi
pop bx
pop ax
jmp return0
ret
open_ok endp
close proc
mov ax,3e00h
int 21h
over: mov ax,4c00h
int 21h
close endp
du_error proc
push dx
push ax
mov dx,offset string1
call tishi
pop ax
pop dx
jmp over
du_error endp
tishi proc
PUSH AX
mov ax,0900h
int 21h
pop ax
ret
tishi endp
du proc
push cx
push dx
push ax
mov cx,1
mov dx,offset buffer
mov ah,3fh
int 21h
jc return
cmp ax,cx
mov al,1ah
jb s
mov al,offset buffer
s: clc
return: pop ax
pop dx
pop cx
ret
du endp
xianshi proc
push si
push dx
push ax
mov si,offset buffer
xor dx,dx
s1: mov dl,
inc si
or dl,dl
jz return2
mov ax,0200h
int 21h
jmp s1
return2: pop ax
pop dx
pop si
ret
xianshi endp
code ends
end start
;功能是读指定文件内容显示在屏幕上，不知道为什么，只读一个字节就报错了谁帮我看看？？
;Μiss＾依然
data segment
string db "file open is wrong$"
string1 db "reading is error$"
filename db '1.txt',0
buffer db 200 dup (?)
data ends
;============================================
;============================================
code segment
assume cs:code,ds:data
start:
mov ax,data
mov ds,ax
clc
;>>>>>>>>>>>>>>>>>>>>>>>>>>
; 打开文件 ;
;>>>>>>>>>>>>>>>>>>>>>>>>>>
mov dx,offset filename
mov ax,3d00h
int 21h
jnc open_ok
;>>>>>>>>>>>>>>>>>>>>>>>>>>
; 不成功提示后退出 ;
;>>>>>>>>>>>>>>>>>>>>>>>>>>
mov dx,offset string
call tishi
jmp over
open_ok proc
mov bx,ax ;为啥给BX？
push ax
push bx
return0:call du
jc du_error
cmp al,1ah
je close
call xianshi
pop bx
pop ax
; jmp return0
; ret
open_ok endp
;>>>>>>>>>>>>>>>>>>>>>>>>>>
; 关闭文件返回 ;
;>>>>>>>>>>>>>>>>>>>>>>>>>>
close proc
mov ax,3e00h
int 21h
over: mov ax,4c00h
int 21h
close endp
;>>>>>>>>>>>>>>>>>>>>>>>>>>
; 读出错后提示后返回 ;
;>>>>>>>>>>>>>>>>>>>>>>>>>>
du_error proc
push dx
push ax
mov dx,offset string1
call tishi
pop ax
pop dx
jmp over
du_error endp
tishi proc
PUSH AX
mov ax,0900h
int 21h
pop ax
ret
tishi endp
;>>>>>>>>>>>>>>>>>>>>>>>>>>
; 读文件过程 ;
;>>>>>>>>>>>>>>>>>>>>>>>>>>
du proc
push cx
push dx
push ax
mov cx,0ffffh
mov dx,offset buffer
mov ah,3fh
int 21h
jc return
cmp ax,cx
mov al,1ah
jb s
mov al,offset buffer
s: clc
return: pop ax
pop dx
pop cx
ret
du endp
xianshi proc
push si
push dx
push ax
mov si,offset buffer
xor dx,dx
s1: mov dl,
inc si
or dl,dl
jz return2
mov ax,0200h
int 21h
jmp s1
return2:pop ax
pop dx
pop si
ret
xianshi endp
code ends
end start{:2_28:}没认真分析，有些地方看的不是很明白！
兄台雷好！！MOV CX,1取一个字节被我改成为四F了，原因是XIANSHIf过程这有INC SI等指令，估计兄台原思路也是只读一次然后逐个显示，不然此处没必要循环~你说是吧
然后就是缓冲区加大了点点~~其它没什么了！！写的非常好~继续加油哈
{:2_33:}
显示目录下的1.txt内容。
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