6个8bits的有符号数相乘的问题，求解答！！
Let us assume to have two arrays of 8-bit signed (2’s complement) integer values (in little endian) denoted asA DB 6 DUP(?)
B DB 6 DUP(?)
It is required to write an 8086 assembly program that:
1. computes the result coming from the multiplication of the 6 values of each array, and store them into two
additional arrays (in two’s complement)
MULT_A DB 6 DUP(?)
MULT_B DB 6 DUP(?)
respectively, (in the running version to be presented at oral exam these results have to be displayed on
the screen)
这个是题目要求，就是要一个数组中存6个8位有符号数的，补码形式，然后让这6个数相乘然后把乘积放到新的数组里面，后面提示
Do not forget that negative numbers in two’s complement can be seen as the “splitting” of one negative and
one positive number. For example: 110101 = 110000 + 000101 (i.e. the first is a negative number while the
second is positive).
就是说补码负数可以拆分成一个负数和正数的和，这个是要提示我啥？是不是要用移位相加来做这个乘法啊？还请大家来帮忙啊！
怎么没人答复我呢，唉！哪位大牛来解救我啊～～～
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