利用栈将二进制转化为十进制的代码..求指点
在这个程序里， StackLen函数的参数是结构体的名字，而不是指向结构体的指针.我想知道为什么他不可以用指针形式作为参数传递..我尝试过用指针作为参数..但是出错了QAQ..求大神指点..#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define STACK_INIT_SIZE 20
#define STACKINCREMENT10
typedef char ElemType;
typedef struct
{
ElemType *base;
ElemType *top;
int stackSize;
}sqStack;
void InitStack(sqStack *s)
{
s->base = (ElemType *)malloc(STACK_INIT_SIZE * sizeof(ElemType));
if( !s->base )
{
exit(0);
}
s->top = s->base;
s->stackSize = STACK_INIT_SIZE;
}
void Push(sqStack *s, ElemType e)
{
if( s->top - s->base >= s->stackSize )
{
s->base = (ElemType *)realloc(s->base, (s->stackSize + STACKINCREMENT) * sizeof(ElemType));
if( !s->base )
{
exit(0);
}
}
*(s->top) = e;
s->top++;
}
void Pop(sqStack *s, ElemType *e)
{
if( s->top == s->base )
{
return;
}
*e = *--(s->top);
}
int StackLen(sqStack s)
{
return (s.top - s.base);
}
int main()
{
ElemType c;
sqStack s;
int len, i, sum = 0;
InitStack(&s);
printf("请输入二进制数，输入#符号表示结束！\n");
scanf("%c", &c);
while( c != '#' )
{
Push(&s, c);
scanf("%c", &c);
}
getchar();// 把'\n'从缓冲区去掉
len = StackLen(s);
printf("栈的当前容量是: %d\n", len);
for( i=0; i < len; i++ )
{
Pop(&s, &c);
sum = sum + (c-48) * pow(2, i);
}
printf("转化为十进制数是: %d\n", sum);
return 0;
}
函数体和调用都改一下，我试过没问题哦 俺来学习谢谢分享 俺来学习谢谢分享
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