查看参考答案
0:只懂得二进制
1:机器语言
2:编译
3:计算机可以识别
4:可以
5:通过编译器
6:查表
7:秦门趁敌人吃饭时发动进攻
1
#include<io.h>
#include<direct.h>
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define MAX 256
long total;
int countLines(const char *filename);
void findAllCodes(const char *path);
void findALLFiles(const char *path);
int countLines(const char *filename)
{
FILE *fp;
int count = 0;
int temp;
if ((fp = fopen(filename, "r")) == NULL)
{
fprintf(stderr, "Can not open the file: %s\n", filename);
return 0;
}
while((temp = fgetc(fp)) !=EOF)
{
if (temp == '\n')
{
count++;
}
}
fclose(fp);
return count;
}
void findAllCodes(const char *path)
{
struct _finddata_t fa;
long handle;
char thePath, target;
strcpy(thePath, path);
if((handle = _findfirst(strcat(thePath, "/*.c"), &fa))!= -1L)
{
do
{
sprintf(target, "%s%s", path, fa.name);
total += countLines(target);
}while (_findnext(handle, &fa) == 0);
}
_findclose(handle);
}
void findALLDirs(const char *path)
{
struct _finddata_t fa;
long handle;
char thePath;
strcpy(thePath, path);
if((handle = _findfirst(strcat(thePath, "/*"), &fa)) == -1L)
{
fprintf(stderr, "The paath %s is wrong!\n",path);
return;
}
do
{
if (!strcmp(fa.name, "." ) || !strcmp(fa.name, ".."))
continue;
if(fa.attrib == _A_SUBDIR)
{
sprintf(thePath, "%s%s", path, fa. name);
findAllCodes(thePath);
findALLDirs(thePath);
}
}while (_findnext(handle, &fa) == 0);
_findclose(handle);
}
int main()
{
char path = ".";
printf("计算中...\n");
findAllCodes(path);
findALLDirs(path);
printf(" 目前你总共写了 %ld 行代码!\n\n", total);
system("pause");
return 0;
}
0.计算机只认识二进制机器语言;
1.机器语言;
2.编码;
3.编译型语言直接编译成机器码,解释型语言编译成中间代码,通过解释器翻译给cpu执行;
4.可以;
5.通过解释器;
6.查表;
7.亲们趁敌人吃饭时发动进攻;
8.C:\Users\山鬼\Desktop
好
动动手答案
感谢感谢感谢感谢
参考答案
参考答案
哇咔咔咔
我要学会c语言
118
复习c
回复
计算机只能识别0和1
机器语言
编译
有无编译
能
..
计算中...
目前你总共写了1539 行代码!
哈哈,不能发图片了
#include <io.h>
#include <driect.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX 256
long total;
int countlines(const char *filename);
void findAllCodes(const char *path);
{
void findAllFiles(const char *path);
int countlines(const char *filename)
FILE *fp;
int count = 0;
int temp;
if ((fp = fopen(filename,"r")) == NULL)
{
fprintf(stderr,"Can not open the file:%s\n",filrname);
return 0;
}
while((temp = fgetc(fp)) !=EDF)
{
if(temp == '\n')
{
count++;
}
}
fclose(fp);
return count;
}
void findAllCodes(const char *path)
{
struct _finddat_t fa;
long handle;
char thePath,target;
strcpy(thePath,path);
if(handle =_findfirst(strcat(thePath,"/*.c"),&fa)) !=-1L)
{
do
{
sprintf(target,"%s/&s",path,fa.name);
total +=countlines(target);
}while (_findnext(handle,&fa) == 0);
}
_findclose(handle);
}
void find ALLDirs(const char *path)
{
struct_finddata_t fa;
long handle;
char thePath;
strcpy(thePath,path);
if(handle = _findfirst)
{
fprintf(stderr,"this path &s is wrong!\n",);
return;
}
do
{
if(!strcmp(fa.name,".")||!strcmp(fa.name,".."))
continue;
if(fa.attrib == _A_SUBDIR )
{
sprintf(thePath,"%s/%s",path,fa.name);
findAllCodes(thePath);
findALLDirs(thePath);
}
}while (_findnext(handle,&fa) == 0);
_findclose(handle);
}
int main()
{
char path =".";
printf(“计算中...\n”);
findAllCodes(path);
findAllDirs(path);
printf("目前你总共写了%1d行代码\n\n",total) ;
system("pause");
return 0;
}
0. 只能读懂机器语言
1. 机器语言
2.编译
3.编译型语言在程序执行之前,有一个单独的编译过程,将程序翻译成机器语言就不用再进行翻译了。解释型语言,是在运行的时候将程序翻译成机器语言
4.能
5.依靠不同平台的解释器
6.用点和杠来传递信息
7.