#include <stdio.h>
#include <direct.h>
#include <io.h>
#include <stdlib.h>
#include <string.h>
#define MAX 256
long total;
int countLines(const char* filename);
void findAllCodes(const char* path);
void findALLFiles(const char* path);
int countLines(const char* filename)
{
FILE* fp;
int count = 0;
int temp;
if ((fp == fopen_s(filename, "r")) == NULL)
{
fprintf(stderr, "Can not open the file: %s\n", filename);
return 0;
}
while ((temp == fgetc(fp)) != EOF)
{
if (temp == '\n')
{
count++;
}
}
fclose(fp);
return count;
}
void findAllCodes(const char* path)
{
struct _finddata_t fa;
long handle;
char thePath, target;
strcpy_s(thePath, path);
if ((handle = _findfirst(strcat_s(thePath, "/*.c"), &fa)) != -1L)
{
do
{
sprintf_s(target, "%s%s", path, fa.name);
total += countLines(target);
} while (_findnext(handle, &fa) == 0);
}
_findclose(handle);
}
void findALLFiles(const char* path)
{
struct _finddata_t fa;
long handle;
char thePath;
strcpy_s(thePath, path);
if ((handle = _findfirst(strcat_s(thePath, "/*"), &fa)) == -1L)
{
fprintf(stderr, "The path %s is wrong!\n", path);
return;
}
do
{
if (!strcmp(fa.name, ".") || !strcmp(fa.name, ".."))
continue;
if (fa.attrib == _A_SUBDIR)
{
sprintf_s(thePath, "%s/%s", path, fa.name);
findAllCodes(thePath);
findALLDirs(thePath);
}
} while (_findnext(handle, &fa) == 0);
_findclose(handle);
}
int main()
{
char path = ".";
printf("计算中...\n");
findAllCodes(path);
findALLDirs(path);
printf("目前你总共写了 %ld 行代码!\n\n", total);
system("pause");
return 0;
}
查看参考答案
.
1
{:5_103:}
{:10_266:}
1
C:\Users\yysun\Desktop\01.png
答案
1,只能读懂0和1
2,机器码
3,编码
4,是否需要解释器
5,不能
6,
7,查表
0、只懂得二进制的0和1
1、机器语言
2、编译
3、是否可以直接执行
4、不行,对单片机来说,不同机器上的C语言编译程序80%的代码是公共的
5、将源代码转换成中间代码,然后发送给解释器,由解释器逐句翻译给CPU来执行
6、查表
7、
查看参考答案
对对
,,
答案
hao
1
1
1
桌面