目前你总共写了0行代码
谢谢小甲鱼
支持!我来学习
来了来了
111
谢谢楼主
1、机器语言0和1
2、解码?
4、不行吧
6、编码和译码
ddddDAAN
?
kandaan
从新打了3遍,才终于成功了,显示的是101行代码
它只能识别01
#include <stdio.h>
#include <unistd.h>
#include <dirent.h>
#include <string.h>
#include <stdlib.h>
#include <sys/stat.h>
#define MAX 256
long total;
int countLines(const char *filename);
int isCode(const char *filename);
void findAllDirs(const char *path);
int countLines(const char *filename)
{
FILE *fp;
int count = 0;
int temp;
if ((fp = fopen(filename, "r")) == NULL)
{
fprintf(stderr, "Can not open the file: %s\n", filename);
return 0;
}
while ((temp = fgetc(fp)) != EOF)
{
if (temp == '\n')
{
count++;
}
}
fclose(fp);
return count;
}
int isCode(const char *filename)
{
int length;
length = strlen(filename);
if (!strcmp(filename + (length - 2), ".c"))
{
return 1;
}
else
{
return 0;
}
}
void findAllDirs(const char *path)
{
DIR *dp;
struct dirent *entry;
struct stat statbuf;
if ((dp = opendir(path)) == NULL)
{
fprintf(stderr, "The path %s is wrong!\n", path);
return;
}
chdir(path);
while ((entry = readdir(dp)) != NULL)
{
lstat(entry->d_name, &statbuf);
if (!strcmp(".", entry->d_name) || !strcmp("..", entry->d_name))
continue;
if (S_ISDIR(statbuf.st_mode))
{
findAllDirs(entry->d_name);
}
else
{
if (isCode(entry->d_name))
{
total += countLines(entry->d_name);
}
}
}
chdir("..");
closedir(dp);
}
int main()
{
char path = ".";
printf("计算中...\n");
findAllDirs(path);
printf("目前你总共写了 %ld 行代码!\n\n", total);
return 0;
}
复制代码
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#include <io.h>
#include <direct.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX 256
long total;
int countLines(const char *filename);
void findAllCodes(const char *path);
void findALLFiles(const char *path);
int countLines(const char *filename)
{
FILE *fp;
int count = 0;
int temp;
if ((fp = fopen(filename, "r")) == NULL)
{
fprintf(stderr, "Can not open the file:%s\n", filename);
return 0;
}
while ((temp = fgetc(fp)) != EOF)
{
if (temp == '\n')
{
count++;
}
}
fclose(fp);
return count;
}
void findAllCodes(const char *path)
{
struct _finddata_t fa;
long handle;
char thePath, target;
strcpy(thePath, path);
if((handle = _findfirst(strcat(thePath, "/*.c"), &fa)) != -1L)
{
do
{
sprintf(target, "%s/%s", path, fa.name);
total += countLines(target);
}while (_findnext(handle, &fa) == 0);
}
_findclose(handle);
}
void findALLDirs(const char *path)
{
struct _finddata_t fa;
long handle;
char thePath;
strcpy(thePath, path);
if((handle = _findfirst(strcat(thePath, "/*"), &fa)) == -1L)
{
fprintf(stderr, "The path %s is wrong!\n",path);
return;
}
do
{
if (!strcmp(fa.name, ".") || !strcmp(fa.name, ".."))
continue;
if( fa.attrib == _A_SUBDIR)
{
sprintf(thePath, "%s/%s", path, fa.name);
findAllCodes(thePath);
findALLDirs(thePath);
}
}while (_findnext(handle, &fa) == 0);
_findclose(handle);
}
int main()
{
char path = ".";
printf("计算中...\n");
findAllCodes(path);
findALLDirs(path);
printf("目前你总共写了 %ld 行代码!\n\n", total);
system("pause");
return 0;
}
查看参考答案
0.
因为计算机只知道指令
1.
二进制
2.
编译
3.
一次性和逐个完成
4.
否
5.
解释器翻译
6.
查表
7.
亲们趁敌人吃饭时发动进攻
{:5_90:}
huifu
C:\Users\86132\Pictures
内容
0. 因为cpu只能识别二进制语言
1. 机器语言
2. 编译
3. 编译:先转化为汇编语言,在转化为机器语言。解释:经过解释器直接转化。
4. 可以
5. 布吉岛
6. 用长音短音组合
7. 亲们趁敌人吃饭时发动进攻