qq
支持
see
0.只会计算0和1
1.机器语言
2.编译
3.前者CPU执行的是机器语言;后者CPU执行的是解释器提供的指令
4.可以
5.字节码将指令发送给解释器
6.摩尔斯电码是一些表示数字的点和划。数字对应单词,需要查找一本代码表才能知道每个词对应的数。用一个电键可以敲击出点、划以及中间的停顿。
7.亲们趁敌人吃饭时进攻
11111111
回复
daan
52行和80行死活解决不了报错{:5_109:}怀疑人生了
python入门也没这么夸张啊
97行代码
#include <io.h>
#include <direct.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX 256
long total;
int countLines(const char *filename);
void findAllCodes(const char *path);
void findALLFiles(const char *path);
int countLines(const char *filename)
{
FILE *fp;
int count = 0;
int temp;
if ((fp = fopen(filename, "r")) == NULL)
{
fprintf(stderr, "Can not open the file:%s\n", filename);
return 0;
}
while ((temp = fgetc(fp)) != EOF)
{
if (temp == '\n')
{
count++;
}
}
fclose(fp);
return count;
}
void findAllCodes(const char *path)
{
struct _finddata_t fa;
long handle;
char thePath, target;
strcpy(thePath, path);
if((handle = _findfirst(strcat(thePath, "/*.c"), &fa)) != -1L)
{
do
{
sprintf(target, "%s/%s", path, fa.name);
total += countLines(target);
}while (_findnext(handle, &fa) == 0);
}
_findclose(handle);
}
void findALLDirs(const char *path)
{
struct _finddata_t fa;
long handle;
char thePath;
strcpy(thePath, path);
if((handle = _findfirst(strcat(thePath, "/*"), &fa)) == -1L)
{
fprintf(stderr, "The path %s is wrong!\n",path);
return;
}
do
{
if (!strcmp(fa.name, ".") || !strcmp(fa.name, ".."))
continue;
if( fa.attrib == _A_SUBDIR)
{
sprintf(thePath, "%s/%s", path, fa.name);
findAllCodes(thePath);
findALLDirs(thePath);
}
}while (_findnext(handle, &fa) == 0);
_findclose(handle);
}
int main()
{
char path = ".";
printf("计算中...\n");
findAllCodes(path);
findALLDirs(path);
printf("目前你总共写了 %ld 行代码!\n\n", total);
system("pause");
return 0;
}
感谢小甲鱼{:10_254:}
1
看看答案吧
回复
做好作业看答案
感谢楼主无私奉献!
C:\Users\Lenovo\Pictures\Screenshots
为啥我是这样的{:10_284:}
复制粘贴也是这样
好用
太棒惹