谁可以帮个忙，把用c写的函数翻译成汇编
如题，函数为：Int Sum（int a，int b）{int c；
c=a+b;
return c;
}
多谢了 我就想学习一下 看书刚学到的方法，用VS写一个c程序，然后编译，逐句调试，再点鼠标右键，选“转到反汇编”，就可以看到汇编的代码了。
int Sum(int a,int b)
{
00991420push ebp
00991421mov ebp,esp
00991423sub esp,0CCh
00991429push ebx
0099142Apush esi
0099142Bpush edi
0099142Clea edi,
00991432mov ecx,33h
00991437mov eax,0CCCCCCCCh
0099143Crep stos dword ptr es:
int c;
c=a+b;
0099143Emov eax,dword ptr
00991441add eax,dword ptr
00991444mov dword ptr ,eax
return c;
00991447mov eax,dword ptr
}
0099144Apop edi
0099144Bpop esi
0099144Cpop ebx
0099144Dmov esp,ebp
0099144Fpop ebp
00991450ret
int main()
{
009913A0push ebp
009913A1mov ebp,esp
009913A3sub esp,0CCh
009913A9push ebx
009913AApush esi
009913ABpush edi
009913AClea edi,
009913B2mov ecx,33h
009913B7mov eax,0CCCCCCCCh
009913BCrep stos dword ptr es:
int x;
x = Sum(3,2);
009913BEpush 2
009913C0push 3
009913C2call @ILT+270(_Sum) (991113h)
009913C7add esp,8
009913CAmov dword ptr ,eax
printf("%d",x);
009913CDmov esi,esp
009913CFmov eax,dword ptr
009913D2push eax
009913D3push offset string "%d" (99573Ch)
009913D8call dword ptr
009913DEadd esp,8
009913E1cmp esi,esp
009913E3call @ILT+310(__RTC_CheckEsp) (99113Bh)
getch();
009913E8call @ILT+130(__getch) (991087h)
}
009913EDxor eax,eax
009913EFpop edi
009913F0pop esi
009913F1pop ebx
009913F2add esp,0CCh
009913F8cmp ebp,esp
009913FAcall @ILT+310(__RTC_CheckEsp) (99113Bh)
009913FFmov esp,ebp
00991401pop ebp
00991402ret 像这样写
gcc 1.c -S 1.s
就行了
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