python小练习（001）：把数字转换成LCD显示模式,Python交流,技术交流,鱼C论坛

忘忧草001 发表于 2016-12-21 23:23:11

不错

dodobar 发表于 2016-12-23 13:42:03

本帖最后由 dodobar 于 2016-12-23 13:43 编辑

dict1={0:[' _','| | ','|_| '],\
1:[' ','| ','| '],\
2:[' _',' _| ','|_'],\
3:[' _',' _| ',' _| '],\
4:[' ','|_| ','| '],\
5:[' _','|_',' _| '],\
6:[' _','|_','|_| '],\
7:[' _','| ','| '],\
8:[' _','|_| ','|_| '],\
9:[' _','|_| ',' _| ']}
number = input('请输入一串数字：')
for i in range(3):
for n in list(number):
print(dict1,end = ' ')
print()

sd小舅子 发表于 2016-12-25 23:35:35

本帖最后由 sd小舅子于 2016-12-25 23:38 编辑

lcd = {0:[' _ ','| |','|_|'],
   1:[' ','|','|'],
   2:[' _ ',' _|','|_ '],
   3:[' _ ',' _|',' _|'],
   4:[' ','|_|','|'],
   5:[' _ ','|_ ',' _|'],
   6:[' _ ','|_ ','|_|'],
   7:[' _ ','|','|'],
   8:[' _ ','|_|','|_|'],
   9:[' _ ','|_|',' _|']}
num = input('请输入数字：')
while True:
if num.isdigit():
   break
else:
   num = input('输入有误，请重新输入：')
for i in range(3):
for each in num:
   print(lcd,end = '')
print()

黯然矢涩 发表于 2016-12-26 11:19:24

厉害啊

飘渺463431810 发表于 2017-1-12 09:35:02

新手还得认真学习了

蛋炒饭妖妖 发表于 2017-1-12 10:26:01

这样字典会不会看起来比较烦？
是不是可以直接用文件把数字的LED存储下来，需要的时候直接读
代码看起来简洁一点

jerryxjr1220 发表于 2017-1-12 10:29:33

蛋炒饭妖妖发表于 2017-1-12 10:26
这样字典会不会看起来比较烦？
是不是可以直接用文件把数字的LED存储下来，需要的时候直接读
代码看起来 ...

当然可以，程序怎么写都可以
可以实现最后的结果，代码看起来简洁，就是目标

蛋炒饭妖妖 发表于 2017-1-12 10:31:13

jerryxjr1220 发表于 2017-1-12 10:29
当然可以，程序怎么写都可以
可以实现最后的结果，代码看起来简洁，就是目标

同意~~~

jerryxjr1220 发表于 2017-1-12 11:03:03

本帖最后由 jerryxjr1220 于 2017-1-12 11:10 编辑

蛋炒饭妖妖发表于 2017-1-12 10:31
同意~~~

不过其实用个列表也很简洁的
pdic = [' _| | |_| ',' | | ',' _ _| |_',' _ _|_| ',' |_| | ',
' _|_ _| ',' _|_|_| ',' _ | | ',' _|_| |_| ',' _|_|_| ']
temp = input('Input the number:')
s = ['','','']
for i in temp:
for j in range(3):
s += pdic
print ('\n'.join(s))

AnlakHui 发表于 2017-1-12 23:26:29

来交作业了，感谢老师分享

jll421740865 发表于 2017-1-18 10:47:39

厉害了经典的题目

jll421740865 发表于 2017-1-18 10:48:26

看到过。。

Kiopler 发表于 2017-2-8 15:54:37

while True:
a = input(r'input the numbers:')
numdict = {
            0:[' _ ','| |','|_|'],
            1:[' ',' | ',' | '],
            2:[' _ ',' _|','|_ '],
            3:[' _ ',' _|',' _|'],
            4:[' ','|_|','|'],
            5:[' _ ','|_ ',' _|'],
            6:[' _ ','|_ ','|_|'],
            7:[' _ ','|','|'],
            8:[' _ ','|_|','|_|'],
            9:[' _ ','|_|',' _|']
            }

show = ['','','']

for each in a:
   each = int(each)
   for i in range(3):
         show += numdict

for each in show:
   print(each)

"""
_    __    _ __ _ _
| ||_| _| |_| |_|_ | |_| |_|
|_|| |__| |_| |_|| |_|_|

"""

我是新人...{:10_266:} ,开始做楼主的每日一练啦，向楼主学习

这个题昨天看到的...一上来根本不会做{:10_247:}看了楼主的答案然后今天独立打出来的

感觉学到了！感谢楼主{:10_266:}

yuzai1702 发表于 2017-2-9 13:08:12

0123就不行

余欲渔 发表于 2017-2-9 13:26:03

看了这里面的其他代码，觉得简洁又比我这个效率高，多做做练习能学到很多啊

def shu():
while True:
   shuru=input('请输入需要转变的数字,输入0000结束:')
   if shuru.isdigit():
         return shuru
   else:
         print('输入有误，请重新输入！！！')
         shu()
def xianshi(shuru):
s=[]
z=[]
x=[]
l=len(shuru)
for i in range(l):
   if shuru=='0':
         s+=[' ','_',' ',' ']
         z+=['|',' ','|',' ']
         x+=['|','_','|',' ']
   elif shuru=='1':
         s+=[' ',' ',' ',' ']
         z+=[' ','|',' ',' ']
         x+=[' ','|',' ',' ']
   elif shuru=='2':
         s+=[' ','_','_',' ']
         z+=[' ','_','|',' ']
         x+=['|','_',' ',' ']
   elif shuru=='3':
         s+=[' ','_',' ',' ']
         z+=[' ','_','|',' ']
         x+=[' ','_','|',' ']
   elif shuru=='4':
         s+=[' ',' ',' ',' ']
         z+=['|','_','|',' ']
         x+=[' ',' ','|',' ']
   elif shuru=='5':
         s+=[' ','_',' ',' ']
         z+=['|','_',' ',' ']
         x+=[' ','_','|',' ']
   elif shuru=='6':
         s+=[' ','_',' ',' ']
         z+=['|','_',' ',' ']
         x+=['|','_','|',' ']
   elif shuru=='7':
         s+=[' ','_',' ',' ']
         z+=[' ',' ','|',' ']
         x+=[' ','_','|',' ']
   elif shuru=='8':
         s+=[' ','_',' ',' ']
         z+=['|','_','|',' ']
         x+=['|','_','|',' ']
   elif shuru=='9':
         s+=[' ','_',' ',' ']
         z+=['|','_','|',' ']
         x+=[' ','_','|',' ']
for i in s:
   print(i,end='')
print(' ')
for i in z:
   print(i,end='')
print(' ')
for i in x:
   print(i,end='')
print('\n')
while True:
shuru=shu()
if shuru=='0000':
   exit()
else:
   xianshi(list(shuru))

k950328 发表于 2017-2-10 14:49:35

学习一下!!!!!!!!!

zealstar 发表于 2017-2-12 14:02:11

本帖最后由 zealstar 于 2017-2-12 14:07 编辑

python看到第10集，还在学习，编了如下代码：
我的LCD构成貌似和楼主不一样……主要是自己想多了……{:10_266:}
def print_num(num_list):
if num_list == []:
   return
count = 0
for i in num_list:
   if i in ['0','2','3','5','6','7','8','9']:
         print(" -- ", end='\t')
   elif i in ['1','4']:
         print(" ", end='\t')
   if count >= 9:
         break
   count += 1
if count < 9:
   print('')
count = 0

for i in num_list:
   if i in ['0','4','8','9']:
         print("||", end='\t')
   elif i in ['1']:
         print(" |", end='\t')
   elif i in ['2','3','7']:
         print(" |", end='\t')
   elif i in ['5','6']:
         print("| ", end='\t')
   if count >= 9:
         break
   count += 1
if count < 9:
   print('')
count = 0

for i in num_list:
   if i in ['0','1','7']:
         print(" ", end='\t')
   elif i in ['2','3','4','5','6','8','9']:
         print(" -- ", end='\t')
   if count >= 9:
         break
   count += 1
if count < 9:
   print('')
count = 0

for i in num_list:
   if i in ['0','6','8']:
         print("||", end='\t')
   elif i in ['1']:
         print(" |", end='\t')
   elif i in ['2']:
         print("| ", end='\t')
   elif i in ['3','4','5','7','9']:
         print(" |", end='\t')
   if count >= 9:
         break
   count += 1
if count < 9:
   print('')
count = 0

for i in num_list:
   if i in ['0','2','3','5','6','8','9']:
         print(" -- ", end='\t')
   elif i in ['1','4','7']:
         print(" ", end='\t')
   if count >= 9:
         break
   count += 1
if count < 9:
   print('')
else:
   print_num(num_list[(count+1):])

number = input("请输入一串数字：")
while not (number.isdigit()):
print("输入非法，请重新输入！")
number = input("请输入一串数字：")
print_num(list(number))

执行结果：

727749815 发表于 2017-2-12 22:15:09

我来贴一下代码LCD=['|','__','|','',' ']
P1=[,,,,,,,,,]
P2=[,,,,,,,,,]
P3=[,,,,,,,,,]

a=input("Please input the number:")
for each_num in a:
i=int(each_num)
for j in P1:
print("%s"%(LCD),end='')
print("",end='')
print()
for each_num in a:
i=int(each_num)
for j in P2:
print("%s"%(LCD),end='')
print("",end='')
print()
for each_num in a:
i=int(each_num)
for j in P3:
print("%s"%(LCD),end='')
print("",end='')

零度非安全 发表于 2017-2-23 18:02:02

lcd_number = { 0:[' _ ','| |','|_|'],\
            1:[' ','|','|'],\
            2:[' _ ',' _|','|_ '],\
            3:[' _ ',' _|',' _|'],\
            4:[' ','|_|','|'],\
            5:[' _ ','|_ ',' _|'],\
            6:[' _ ','|_ ','|_|'],\
            7:[' _ ','|','|'],\
            8:[' _ ','|_|','|_|'],\
            9:[' _ ','|_|',' _|'] }

while True:

input_number = input('Input the numbers:')

for i in range(3):
for j in input_number:
   print(lcd_number,end = ' ')
print('')

solomonxian 发表于 2017-3-22 21:22:51

本帖最后由 solomonxian 于 2017-3-22 21:53 编辑

def ledNum(number):
"""使传入的数字变成LED显示的模样打印出来"""
s = """
_ __ _____
| | |_| _||_||_ |_ ||_||_|
|_| | |__|| _||_|||_| _|"""
num = str(number)
if not num.isdigit():
   return print("请输入数字")
s_num = 1
# 只有3*n，不要怕嵌套循环
for i in range(3):
for j in num:
         n = int(j)*3 + s_num
         print(s, end="")
   print("")
   s_num += 31

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